Solution equation: 3x + 22 = 5x

Solution equation: 3x + 22 = 5x

3X+22=5X
22=5x-3x
2x=22
x=11
22=5x-3x
2x=22
x=11
When calculating 3 (4 + 1) (the square of 4 + 1), a student wrote 33 as 4-1 and found that he could continuously use the square difference formula to calculate:
3 (4 + 1) (square + 1 of 4) = (4-1) (4 + 1) (square + 1 of 4) = (Square-1 of 4) (square + 1 of 4) = Square-1 of 16. Try to calculate the value of (2 + 1) (2 ^ 2 + 1) (2 ^ 4 + 1) (2 ^ 8 + 1)... (2 ^ 1024 + 1) - 2 ^ 2048
Because 2-1 = 1
therefore
Original formula = (2-1) (2 + 1) (2 ^ 2 + 1) (2 ^ 4 + 1) (2 ^ 8 + 1)... (2 ^ 1024 + 1) - 2 ^ 2048
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)...(2^1024+1)-2^2048
Continuous application of square difference formula
=2^2048-1-2^2048
=-1
Let the domain of definition of function y equal to one part of root x-a be a, and the solution set of inequality 2 Λ x2 < 4 be B if B &; a find the value range of real number a
The definition field of function y equal to 1 / 2 of root x-a is a = {XIX > a}
The solution set of inequality 2 Λ x2 < 4 is b = {Xi radical 2}
If the value of a (X-5) is not less than that of x-4, the value range of X is obtained
a(x-5)/4>x-4
0.25ax-1.25a>x-4
0.25ax+4>x+1.25a
0.25ax-x>1.25a-4
x(0.25a-1)>1.25a-4
x>(1.25a-4)/(0.25a-1)
x>(5a+16)/(a-4)
The greater than sign is regarded as the greater than or equal to sign
X is greater than or equal to (5a + 16) / (A-4)
6-5x = 3x + 22 to solve the equation
6-5x=3x+22
-5x-3x=22-6
-8x=16
x=-2
6-5x=3x+22
3x+5x=6-22
8x=-16
x=-2
-8x=22-6
-8x=16
x=-2
6-5x=3x+22
-22+6=3x+5x
-16=8x
The solution is x = - 2
So the solution of the original equation is x = - 2
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When calculating 3 (4 + 1) (the square of 4 + 1), a student wrote 33 as 4-1 and found that he could use the square difference continuously
Calculation: 3 (4 + 1) (4's square + 1) = (4-1) (4 + 1) (4's square + 1) = (4's Square-1) (4's square + 1) = 16's Square-1 = 255
According to the experience of students, calculate: (1 + 1 / 2) (the square of 1 + 1 / 2) (the fourth power of 1 + 1 / 2) (+ 8 power of 1 / 2) + 15 power of 1 / 2
Calculation: (1 + 1 / 2) (the square of 1 + 1 / 2) (the 4th power of 1 + 1 / 2) (+ the 8th power of 1 / 2) + the 15th power of 1 / 2. Note: Happy New Year! Your question may be wrong. The fourth bracket in the above formula is estimated to be missing a 1. Please check it. For convenience, it is agreed in advance that a ^ n is the nth power of A
The denominator is multiplied by (1-1 / 2).
Given the set a = {x ﹤ 1 or X ﹥ 2}, B = {x ﹤ 4x + a ﹤ 0}, if B a = {1,2}, B &; a, the value range of real number a is obtained
B if a?
Correct answer deleted..
It is known that B = {X / x = 4}
If the algebraic formula a (X-5) / 4 of X is not less than x-4, the range of value of X is fast,
a(x-5)/4≥x-4
ax-5a≥4x-16
(a-4)x≥-21
be
a>4,x≥-21/(a-4)
A = 4, X is any real number
A
Solving equation 35 (X-2) - 15 (5x-6) = (22x-63) - 21 (3x-4)
35（x-2）-15（5x-6）=（22-63）-21（3x-4）
35（x-2）-15（5x-6）=（22x-63）-21（3x-4）
35x-70-75x+90=22x-63-63x+84
-40x+20=-41x+21
41x-40x=21-20
X=1
35（x-2）-15（5x-6）=（22X-63）-21（3x-4）
35X-70-75X-90=22X-63-63X+84
-40X=-41X+21+160
X=181
The original formula is 35x-70-75x-90 = 22x-63-63x + 84
x=181
Left: 35x-75x-70 + 75 = - 40x + 5
Right: 22x-63x-63 + 84 = - 41x + 21
x=16
Is the middle 22-63 or 22x-63
35（x-2）-15（5x-6）=（22x-63）-21（3x-4）
35x-70-75x+90=22x-63-63x+84
35x-75x-22x+63x=84-63-90+70
X=1
35（x-2）-15（5x-6）=（22x-63）-21（3x-4）
35x-70-75x+90=22x-63-63x+84
-45x+20=-41x+21
45x-41x=20-21
4x=-1
x=-1/4
35(x-2)-15(5x-6)=(22-63)-21(3x-4)
35x-70-75x+90=-41-63x+84
20-40x=43-63x
-40x+63x=43-20
23x=23
X=1
Use the square difference formula to calculate: 100 & # 178; - 99 & # 178; + 98 & # 178; - 97 & # 178; + 96 & # 178; - 95 & # 178; +... + 2 & # 178; - 1 & # 178;
100²-99²+98²-97²+96²-95²+...+2²-1²
=100+99+98+97+…… +2+1
=100(100+1)/2=5050