If the equation x & # 178; - (m-2) x + 4 = 0 has real roots, find the value range of real number M

If the equation x & # 178; - (m-2) x + 4 = 0 has real roots, find the value range of real number M

X & # 178; - (m-2) x + 4 = 0 has real roots
Discriminant = (- (m-2)) ^ 2-4 * 4 > = 0
(m-2)^2>=16
M-2 > = 4 or m-2 = 6 or M
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The "H operation" of positive integer n is: when n is odd, H = 3N + 13; when n is even, H = n × (1 / 2) × (1 / 2) × (where h is an odd number). For example, the result of the number 3 after one "H operation" is 22, the result after two "H operations" is 11, and the result after three "H operations" is 46
(1) After 257 times of "H operation", the result is obtained;
(2) If the result of "H operation" is always constant a, find the value of A
Divide the folding angle of B, B, B, B, C into the degree of B, B, B, D, B, B, C, B, D, B, B, C, B, C, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B, B
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From the first line to the fifth, the sixth and the seventh
The first operation result of 257 is 784, the second operation result is 49, the third operation result is 160, the fourth operation result is 5, the fifth operation result is 7, the sixth operation result is 34, the seventh operation result is 17, the eighth operation result is 64, the fifth power of 2, the ninth operation result is 1, and the tenth operation result is 16257, so the final result is 1
When n is the m-th power of 2, the result of H operation "2" is always constant a = 1
(1) After 257 times of "H operation", the result is obtained;
257 -- 784 -- 49 -- go on, and the repetition number in front of you will go round. Do it yourself.
(2) If the result of "H operation" is always constant a, find the value of A
A satisfies 3A + 13 = 2 ^ n * a
So the solution of a = 13 / (3-2 ^ n) is a = 13
There are three questions, but they are not separated. I'm sorry
3x + 8 = 20, then 3.5x + 24 =?
The solution is: from 3x + 8 = 20, x = 4, into 3.5x + 24 = 3.5 * 4 + 24 = 38
Find the unknowns x.x-19 2, x-12.3 2 3
x=21,x=16.1
The equation x2 + y2-2 (M + 3) x + 2 (1-4m Square) y + 16m fourth power + 9 = 0 represents a circle. 1. Find the value range of real number m; 2. The value range of radius r of the circle
x2+y2-2(m+3)x+2(1-4m2)y+16m4+9=0
X & # 178; - 2 (M + 3) x + (M + 3) & # 178; + Y & # 178; + 2 (1-4m & # 178;) y + (1-4m & # 178;) & # 178; = (M + 3) & # 178; + (1-4m & # 178;) & # 178; - 16m power-9
[x - (M + 3)] ² + [y + (1-4m & #178;)] ² = M & #178; + 6m + 9 + 1-8m & #178; + 16m to the fourth power - 16m to the fourth power - 9
[x-(m+3)]²+[y+(1-4m²)]²= -7m²+6m+1
∴-7m²+6m+1>0
7m²-6m-1
What is the highest degree term of a polynomial? How many times is a polynomial? Urgent!
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It's the polynomial with the most degree
for instance
3X*2Y+X+Z
The highest term in it is twice, twice trinomial
20+5x-4=3x
20+5x-4=3x
16+5x=3x
5x-3x=-16
2x=-16
x=-8
Is this how much x equals?
How to play the unknown x
Open the Greek letter enter in the input soft keyboard, and the one before it is
It is known that there is a point P (a, b) on the image of the inverse scale function y = K / x, and a, B are the two roots of the equation y & # 178; - 4M-2 = 0
And the distance from point P to the origin
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There is a point P (a, b) on the image of inverse scale function y = K / X,
therefore
ab=k
And a, B are the two roots of the equation y & # 178; - 4Y-2 = 0,
therefore
ab=-2
a+b=4
therefore
k=-2
The distance from point P to the origin
=√a²+b²
=√(a+b)²-2ab
=√16+4=√20=2√5.
In the problem, the equation y & # 178; - 4M-2 = 0 should be y & # 178; - 4Y-2 = 0, otherwise, we can only derive the algebraic expression of K expressed by M; the following solution is based on this.
a. B is the two roots of the equation y & # 178; - 4M-2 = 0
a+b =4； a*b = -2；
P (a, b) on y = K / x = = > b = K / a = = > k = AB = - 2;
... unfold
In the problem, the equation y & # 178; - 4M-2 = 0 should be y & # 178; - 4Y-2 = 0, otherwise, we can only derive the algebraic expression of K expressed by M; the following solution is based on this.
a. B is the two roots of the equation y & # 178; - 4M-2 = 0
a+b =4； a*b = -2；
P (a, b) on y = K / x = = > b = K / a = = > k = AB = - 2;
If the distance from P to the origin is set to OP, then:
OP² = a² + b²
= (a+b)² -2ab
= 4² -2*(-2) =20
∴ OP = √20 =2√5
The distance from P to the origin is set to 2 √ 5
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Times of 2x-3
The degree of XY ^ 3 + 1
The times of 2Ab + Wu
The degree of 2 / 5x-6y ^ 3
Items and times of 4A ^ B ^ 2-4ab + B ^ 2
The term and degree of x ^ 3 + 2y-x
-Terms and times of 3x-x ^ 2Y + 2
Items and times of m ^ 3-2m ^ 2n ^ 2 + 3N ^ 2
The times of 2x-3 are 1; the times of XY ^ 3 + 1 are 4; the times of 2Ab + 2 are 2; the times of 2 / 5x-6y ^ 3 are 3; the items and times of 4A ^ B ^ 2-4ab + B ^ 2 are 3; the items and times of x ^ 3 + 2y-x are 3; the items and times of - 3x-x ^ 2Y + 2 are 3M ^ 3-2m ^ 2n ^ 2 + 3N ^ 2 are 4
The number of 2x-3 is 1;
The degree of XY ^ 3 + 1 is 4;
The number of 2Ab + is 2;
The degree of 2 / 5x-6y ^ 3 is 3;
The term and times of 4A ^ B ^ 2-4ab + B ^ 2 are 3;
The term and degree of x ^ 3 + 2y-x are 3;
-The term and degree of 3x-x ^ 2Y + 2 are 3
The term and degree of m ^ 3-2m ^ 2n ^ 2 + 3N ^ 2 are 4;