3x-5x merge congeners

3x-5x merge congeners

3x-5x
=-2x
X = a + BX 1 / 3, 1 / 3 is power, a, B are constant, X is unknown
Three values are obtained by MATLAB
x1= a+b*(1/6*(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)+2*b/(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3))
x2= a+b*(-1/12*(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)-b/(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)+1/2*i*3^(1/2)*(1/6*(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)-2*b/(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)))
x3=a+b*(-1/12*(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)-b/(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)-1/2*i*3^(1/2)*(1/6*(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)-2*b/(108*a+12*(-12*b^3+81*a^2)^(1/2))^(1/3)))
What do you want
a. B is a constant, then x comes out. Question: A and B are constants, but 1 / 3 is 1 / 3 power, so they are higher order equations...
Given that the equation x ^ 2 + y ^ 2 (M + 3) x + 2 (1-4m ^ 2) y + 16m ^ 4 + 9 = 0 represents a circle, find the value range of real number M
If
x^2+y^2+2(m+3)x+2(1-4m^2)y+16m^4+9=0
[x-(m+3)]^2+[y-(1-4m^2)]^2=m^2+6m+1
Thinking R ^ 2 = m ^ 2 + 6m + 1 > 0
m^2+6m+1>0
m> - 3 + 2 √ 2 or M
Using addition, subtraction, multiplication and division, how to make 3 5's and 1's get 24 (each number is used once)
1:5 × (5 - 1 ÷ 5)
2:5 × (5 - (1 ÷ 5))
3:(5 - 1 ÷ 5) × 5
4:(5 - (1 ÷ 5)) × 5
Find the law: - x, 2x ^ 2, - 3x ^ 2, 4x ^ 2 ,-19x^19,20x^20…
And write the 2009 monomial,
(-1)nx^n
Three fifths: 2.5 = 6: X to find the unknown x
Three fifths: 2.5 = 6: X
3/5X=2.5X6
3/5X=15
X=15÷3/5
X=25
2.4 questioning: process
Given that the equation x ^ 2 + y ^ 2-2 (M + 3) x + 2 (1-4m ^ 2) y + 16m ^ 4 + 9 = 0 represents a circle, find the value range of real number M
Given that the equation x ^ 2 + y ^ 2-2 (M + 3) x + 2 (1-4m ^ 2) y + 16m ^ 4 + 9 = 0 represents a circle, find the value range of real number M
Who can write more detailed steps
Write down any formula
-1/7
A group of students at the speed of 10.5km/h outside the school activities, walk for half an hour, the school sent a correspondent at the speed of 15km / h to catch up with the team according to the original road, ask the correspondent how many hours can catch up with the student team, set. Then the correspondent to catch up with the student team traveled km
Set up correspondents to catch up with students in X hours
When the correspondent caught up with the students, he traveled x * 15 kilometers
Set up equations according to questions
15X=10.5(X+0.5)
15X=10.5X+5.25
4.5X=5.25
X=35/3
Correspondents can catch up with students in 35 / 3 hours
x-0.3x-0.5x=20
10x-3x-5x = 200 this step is to multiply all the numbers by 10 at the same time
(10-3-5) x = 200. This is a merging congener
2x=200
x×2÷2=200÷2
x=100
x-0.3x-0.5x=20
0.2x=20
x=100
I hope I can help you
x-0.3x-0.5x=20 o.2X=20 X=100
Find the unknown number 5x-20% x = 19.2
5x-0.2x=19.2