Factorization 7x ^ 4 + 11x ^ 2-6

Factorization 7x ^ 4 + 11x ^ 2-6

7x^4+11x^2-6=（7x^2-3）（x^2+2）
Factorization of x ^ 3 + x ^ 2 + 11x + 6
factor(x^3+x^2+11*x+6)
ans =
x^3+x^2+11*x+6
It has been checked by computer
There is no solution in the range of integers
^It means to be square. The following number is the number of power
For example, the above formula can be written as the third power of x plus the square of X
^What do you mean
It can't be decomposed in the range of rational number
How to factorize x ^ 2-11x – 10 = 0
This can't be factorized
If it is
X ^ 2-11x + 10 = (x-1) (X-10) is OK
Factorization: X & sup2; - 11x & sup2; Y & sup2; + (Y & sup2;) & sup2;
Try to solve the problem by formula method
Original formula = (x-y2) 2-9x2y2
=（x-y2）2-（3xy）2
=（x-y2+3xy）×（x-y2-3xy）
I haven't done this for a long time. It should be like this
No matter what the real number of M is, the value of the polynomial 2m & # 178; - 6m + (15 / 2)) must be greater than or equal to________ .
2m²－6m＋15/2
=2(m^2-3m+9/4)-9/2+15/2
=2(m-3/2)^2+3
≥3
The equation AX2 - (3a + 1) x + 2 (a + 1) = 0 has two unequal real roots X1 and X2, and x1-x1x2 + x2 = 1-A, then the value of a is ()
A. 1b. - 1C. 1 or - 1D. 2
According to the meaning △ 0, namely (3a + 1) 2-8a (a + 1) > 0, namely a2-2a + 1 > 0, (A-1) 2 > 0, a ≠ 1, ∵ the equation AX2 - (3a + 1) x + 2 (a + 1) = 0 of X has two unequal real roots X1 and X2, and x1-x1x2 + x2 = 1-A, ∵ x1-x1x2 + x2 = 1-A, ∵ X1 + x2-x1x2 = 1-A, ∵ 3A + 1a-2
X-12.56 = 15.7 to solve the equation
x-12.56= 15.7
x=12.56+ 15.7
x=28.26
x-12.56= 15.7
x=28.26
If the inequality X & #178; - 4|x| + 2-m on X
m=-1
When x > 0, | x | = x, the original inequality is reduced to (X-2) ^ 2
On the equation AX ^ 2 - (3a + 1) x + 2 (a + 1) = 0 of X, there are two equal real number roots X1 and X2, and x1-x1x2 + x2 = 1-m, find the value of M
Note that there are two "equal" real roots, not two "unequal" real roots!,!
If the equation has two equal real roots, then △ = (3a + 1) ^ 2-4 * a * 2 (a + 1) = (9a ^ 2 + 6A + 1) - 8A ^ 2-8 = a ^ 2 + 6a-7 = (A-1) (a + 7) = 0A = 0, or a = - 7x1-x1x2 + x2 = 1-m (x1 + x2) - x1x2 = 1-m (3a + 1) / A-2 (a + 1) / a = 1-m, when a = 1, 1-m = 4-4 = 0m = 1, when a = - 7, 1-m = 20 / 7-12 /
This is the application of Weida theorem and the discriminant method of △ first of all, (3a 1) ^ 2 - 4 * a * 2 (a 1) = 0, then I miscalculated, sorry.
Solution equation: 80% x-24 = 56% X
80%X-24=56%X
0.8x-24=0.56x
(0.8-0.56)x=24
0.24x=24
x=100
80%X-24=56%X
80%X - 56%X =24
24%X=24
X=100
80%X-24=56%X
80%X-56%X=24
24%X=24
x=24÷ 24%
x=100