If the fractional equation 2 + 1-kx / X-2 = 1 / 2-x has an increasing root, then K=

If the fractional equation 2 + 1-kx / X-2 = 1 / 2-x has an increasing root, then K=

The fractional equation 2 + 1-kx / X-2 = 1 / 2-x has increasing roots
The increasing root is x = 2
The denominator of the original equation is removed to get 2 (X-2) + 1-kx = - 1
X = 2
0+1-2k=-1
K=1
According to the general steps of solving the fractional equation, the fractional equation K / (x + 1) (x-1) + 1 = 1 / x + 1 about X is solved, the increasing root x = - 1 appears, and the value of K is obtained
On the fractional equation K / (x + 1) (x-1) + 1 = 1 / x + 1 of X, the increasing root x = - 1 appears and the value of K is obtained
K is a molecule
(x + 1) (x-1) is the denominator
1 is a constant term
After the equal sign is
One is a molecule
The denominator is x + 1
Remove the denominator and multiply the simplest common denominator (x + 1) (x-1) on both sides of the equation to obtain:
K + X & sup2; - 1 = X-1, shift term
K = x-x & sup2; (substituting increasing root x = - 1)
k=-1-(-1)²=-1-1=-2
So k = - 2
First, the fractional equation is transformed into an integral equation, and then x = - 1 is brought in to get K.
You're always going to get that integral equation.
It is known that the domain of definition of F (x) is a non-zero real number and satisfies the analytic formula of finding f (x) by 3f (x) + 2F (1 / x) = 4x
3f(x)+2f(1/x)=4x （1）
Let x = 1 / x, then 1 / x = X
therefore
3f(1/x)+2f(x)=4/x (2)
(1)*3-(2)*2
9f(x)-4f(x)=12x-8/x=(12x^2-8)/x
So f (x) = (12x ^ 2-8) / (5x)
If P (x, y) is a moving point on the ellipse 2x2 + 3y2 = 12, then the maximum value of X + 2Y is______ .
By transforming the ellipse 2x2 + 3y2 = 12 into a standard equation, we get that x26 + y24 = 1, and the parameter equation of this ellipse is: x = 6cos θ y = 2Sin θ, (θ is a parameter) ‖ x + 2Y = 6cos θ + 4sin θ, and (x + 2Y) max = 6 + 16 = 22
How to solve 4 = 3x & # 178; + X & # 179
x³+3x²-4=0
x³-x² +4x²-4=0
x²(x-1)+4(x+1)(x-1)=0
(x-1)(x²+4x+4)=0
(x-1)(x+2)²=0
∴x=1 x=-2
4=3x²+x³
x³+3x²-4=0
x³-x²+4x²-4=0
x²(x-1)+4(x²-1)=0
x²(x-1)+4(x+1)(x-1)=0
(x-1)[x²+4(x+1)]=0
(x-1)(x²+4x+4)=0
(x-1)(x+2)²=0
X-1 = 0 or (x + 2) ² = 0
X = 1 or x = - 2
As an example, I want to make a summary of the rules of the usage of the quantifier
What I want is a summary of the rules of words. Such as a piece of paper, a bow, a face, "paper, face" and other nouns used after a piece of paper.
The emergence and historical evolution of the Quantifier "Zhang" in Baidu Library
I'll pass it on to you if you're in trouble,
At first, Zhang was only used as the quantifier of bow and crossbow. Later, Zhang was extended to the objects that can be stretched, spread and opened
For example, face. When Zhang is used as a quantifier, it is usually accompanied by a certain expression (no expression is also emphasizing expression) - this is dynamic
Zhang, quantifier. Here is a piece of paper
After summing up the use of numerals: 1. It is often used in combination with numerals.
Zhang, quantifier. Here is a piece of paper
Features: 1. Use after numerals. It is often used in combination with numerals.
Given the fixed point C and ellipse x ＾ 2 + 3Y ＾ 2 = 5
Given the fixed point C and the ellipse x ＾ 2 + 3Y ＾ 2 = 5, the moving line passing through C intersects the ellipse at two points a and B, and the abscissa of the midpoint of a and B is - 1 / 2. Whether there is a point m on the x-axis, so that the vector Ma · MB is a constant. If there is, the coordinate of M is obtained; if not, the reason is given
Sorry, forget it
Fixed point C (- 1,0)
Let the linear AB equation be y = K (x + 1) and the elliptic equation be (3K & sup2; + 1) x & sup2; + 6K & sup2; X + 3K & sup2; - 5 = 0. According to Weida's theorem, X1 + x2 = - 6K & sup2; / (3K & sup2; + 1), x1x2 = (3K & sup2; - 5) / (3K & sup2; + 1) the abscissa of the midpoint of a and B is - 1 / 2, so X1 + x2 = - 6K & sup
What are the coordinates of point C?
Equations X & # 178; - Y & # 178; - 3x + 5Y = 0, x-y-1 = 0
Equations
x²-y²-3x+5y=0,（1）
x-y-1=0 （2）
Y = X-1 (3) from (2)
Substituting (3) into (1) yields:
x²-(x-1)²-3x+5(x-1)=0
It is found that 4x-6 = 0
x=1.5
y=0.5
The following propositions are represented by the symbol &; or &
1. All the real numbers a, B, the equation AX + B = 0 have unique solutions
2. There is a triangle whose sum of internal angles is not equal to 180 degrees
1.∀a,b∈R,∃!x∈R,s.t.ax+b=0
2.∃△ABC,s.t.∠A+∠B+∠C≠180°
Let P (x, y) be a moving point of the ellipse 2x + 3Y = 12, and obtain the value range of X + 2Y
2X + 3Y = 12
x^2/6+y^2/4=1
Let x = root 6 cosa, y = 2sina
X + 2Y = radical 6cosa + 4sina = radical (6 + 16) sin (a + m)
Again - 1