What is the square of complex I?

What is the square of complex I?

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The known set P = {X / radical 2 + 1
Solve N set, because √ 2 + 1 ≤ x ≤ 3
So n = {y | 1 ≤ y ≤ 3}
In M set, X & # 178; - (a + 1) x + a ≤ 0
So (x - a) (x - 1) ≤ 0
To make the M range small
So a can be taken as 1, and a cannot be smaller than 1
In the equal ratio sequence {an}, a2-a1 = 2, and 2A2 is the mean of the equal difference of 3A1 and A3. Find the first term, common ratio and the sum of the first n terms of the sequence {an}
Let the common ratio of the sequence of equal ratio numbers be Q. from the known results, a1q-a1 = 2, 4a1q = 3A1 + a1q2 can be obtained simultaneously, A1 (Q-1) = 2, q2-4q + 3 = 0  q = 3A1 = 1 or q = 1 (rounding off) ｜ Sn = 1 − 3N1 − 3 = 3N − 12
What is the square of I in the complex number
-1
-1
Zero
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-1. It's too simple
Let the square of a = 2x - ax + B = 0, the square of B = 6x + (a + 2) x + B = 0, and the intersection of a and B is equal to {1 / 2}
urgent need
A = 2x ^ 2 + 2x-3 / 2 = 0, B = 6x ^ 2-3 / 2 = 0, a = {- 3 / 2,1 / 2} B = {- 1 / 2,1 / 2} so a and B = {- 3 / 2, - 1 / 2,1 / 2}
The formula of {a 1 + a 2} is known, and the sum of a 3 + a 2} is the general formula
A2 + 6 is the median of the equal difference between A1 and A3
2（a2+6）=a1+a3 ①
a1+a2+a3=39 ②
Bring ① into ② (to eliminate a1 + a3)
So A2 = 9
In ②, A1 = A2 / Q, A3 = a2q are brought in
Q = 3, or q = 1 / 3
Find that the equal ratio sequence {an} is an increasing sequence, Q > 1
So q = 3
a1=3
So an = 3 ^ n
Complex 2 + I square equals
(2+i )^2==2^2+4i+i^2=4+4i-1=3+4i
(2+i )^2=4+4i-1=3+4i
(2+i )^2=4+4i-1=3-4i
It is known that the set a is equal to {the square of X / ax + 2x + 1 = 0}, and B = {A / such that there is only one element in a}
① When a = 0, there is only one element - 1 / 2 in a
② When △ = 4-4a = 0 → a = 1, there is only one element - 1 in a
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It is known that A1 = 1, and A2 is the median of the equal difference of A1 and a3-1 in the equal ratio sequence {an}. (I) find the general term formula of the sequence {an}; (II) if the sequence {BN} satisfies BN = 2N-1 + an (n ∈ n *), find the first n term and Sn of {BN}
(1) Let the common ratio of the sequence {an} be q, ∵ A2 be the median of the equivalences of A1 and a3-1, A1 = 1, ∵ 2A2 = a1 + (a3-1) = A3, ∵ q = a3a2 = 2, ∵ an = a1qn − 1 = 2N-1, (n ∈ n *) (Ⅱ) ∵ BN = 2N-1 + an, ∵ Sn = (1 + 1) + (3 + 2) + (5 + 22) + +（2n-1+2n-1）=[1+3+5+… +...
What is the square of the complex number (1 + I / 2 I)
[-2i/(1+i)]²
=(2i)²/(1+i)²
=(2i)²/(1+2i-1)
=(2i)²/(2i)
=2i
-2i