If the ellipse MX ^ 2 + my ^ 2 and the line x + Y-1 = 0 are compared with two points a and B, and the slope k of the line passing through the origin and the midpoint of the line AB is two-thirds root sign, then n / M =? Detailed process The answer is root 2 / 2

If the ellipse MX ^ 2 + my ^ 2 and the line x + Y-1 = 0 are compared with two points a and B, and the slope k of the line passing through the origin and the midpoint of the line AB is two-thirds root sign, then n / M =? Detailed process The answer is root 2 / 2

Simultaneous MX ^ 2 + NY ^ 2 = 1, x + Y-1 = 0, eliminating y, we get (M + n) x ^ 2-2nx + n ^ 2-1 = 0A, the abscissa x1, X2 of B is the solution of the above equation a, the abscissa of the midpoint of B is (x1 + x2) / 2x1 + x2 = 2n / (M + n) a, the abscissa of the midpoint of B is n / (M + n) substituted into the linear equation x + Y-1 = 0A, the ordinate of the midpoint of B is m / (M + n) passing through the origin
Given the length of two right angles of a right triangle, how to use a calculator to find the angle of the other two angles as quickly as possible?
Seek concrete operation step! What I use is that kind of trigonometric function calculator!
How to press on the calculator?
If the right angle sides are a and B,
∠A=arctan(a/b)
∠B=arctan(b/a)
Calculator for students: first press shift in the upper left corner, then press Tan, and then press a / b=
Previous calculators, first press a / b = and then the function key 2ndf in the upper left corner, and then press tan
First, we use the formula A & sup2; + B & sup2; = C & sup2; to get the value of the hypotenuse C, and then we get a / C and B / C respectively,
Finally, a = arc sin (A / C) and B = arc sin (B / C) are obtained respectively.
Given the arithmetic sequence {an}, A1 = a, tolerance d = 1. If BN = an ^ 2-A (n + 1) ^ 2, try to judge whether the sequence {BN} is arithmetic sequence, and prove your conclusion
A = 1, is the arithmetic sequence, otherwise, it is not
5x-(20-x)=68
5x-(20-x)=68
5x-20+x=68
6x-20=68
6x =68+20
6x =88
X = 88 divided by 6
X = self calculation
When the ellipse AX2 + BY2 = A and the line y = 1-x intersect at two points a and B, and the slope of the line passing through the origin and the midpoint of the line AB is 2 / 2, then the value of a / B is
This is the classic topic of ellipse and line intersection
Well, you can also eliminate the ellipse equation by substituting y
We can get the quadratic equation of one variable about X
If the discriminant in the quadratic equation of one variable is > 0, assuming that the coordinates of points a and B are (x1, Y1), (X2, Y2), the coordinates of the midpoint of line AB can be obtained
The relationship between x 1 + x 2 and x 1 * x 2 is known by WIDA's theorem, and then the value of a / B is obtained according to the slope
Write the Veda theorem, but how to write the value of a / B according to the slope?
"The slope of the straight line passing through the origin and the midpoint of the line AB" is direct (Y1 + Y2) / (x1 + x2), Y1 + Y2 can be expressed by Veda's theorem and the linear equation by the formula containing a and B, and then the known slope is equal to the root 2 of 2 to get the relationship of a / b
Use the two-point formula. Set but not seek
Triangle angle calculator tan28 degrees
zero point five three one seven zero nine
tan28°=0.531709431
I'm a teacher. Thank you
Known sequence {an} and {BN} satisfy: A1 = x, a (n + 1) = 2 / 3an + n-4, BN = (- 1) ^ n * (an-3n + 21), where x is real number and N is positive integer
It is known that the sequence {an} {BN} satisfies the N times (an-3n + 21) of A1 = x, an + 1 = 2 / 3an + n-4, BN = (- 1), where x is a real number and N is a positive integer 1. For any number x, it is proved that the sequence {an} is not an equal ratio sequence. 2
Square of (x + 5) - (X-2) (x-3) dear friends, how can we get this step! = square of X + 10x + 25 - (square of x-5x + 6)
I didn't listen to the class carefully in the morning. I don't know how I got this movie. Teach me,
（x+5)^2-(x-2)(x-3)
=x^2+2*5*x+5^2-(x*x-3*x-2*x+2*3)
=x^2+10x+25-(x^2-5x+6)
=x^2+10x+25-x^2+5x-6
=15x+19
cross multiplication
I converted (X-2) (x-3) to (X-2) (x-3)! Kneel down and beg
The ellipse ax ^ 2 + by ^ 2 = 1 and the straight line x + y = 1 intersect at two points ab. if | ab | = 2 √ 2 and the slope of the line between the midpoint C of AB and the center of the ellipse is √ 2 / 2, find the real number
The value of ab
Let a (x1, Y1), B (X2, Y2), C (x0, Y0)
# {178; # by},
{x+y-1=0
（a+b)x²-2bx+b-1=0
We can get: {2B + x 2 / (a)
{x1·x2=（b-1）/（a+b）
dAB=√2·√[2b/（a+b）]²-[4(b-1)/(a+b)]=2√2
The results are as follows: a-178; + b-178; + 3ab-a-b = 0
{x0 = (x1 + x2) / 2, that is {x0 = B / (a + b)
{y0=(y1+y2)/2=(-x1+1-x2+1)/2 {y0=a/（a+b）
koc=y0/x0=a/b=√2/2 ②
① The solution is: a = 1 / 3, B = √ 2 / 3
If the two sides of the right triangle are known to be 2, then the third side of the right triangle should be 6 ()
A. No more than 2B. 210C. 42 or 210D
According to Pythagorean theorem, there are two cases: (1) when the third side is a hypotenuse, the length of the third side is 62 + 22 = 210; (2) when the hypotenuse is 10, the length of the third side is 62 − 2 & nbsp; 2 = 42; so choose C