If the value of the algebraic formula 2x + 33 is nonnegative, then the value range of X is () A. x≥32B. x≥-32C. x＞32D. x＞-32

If the value of the algebraic formula 2x + 33 is nonnegative, then the value range of X is () A. x≥32B. x≥-32C. x＞32D. x＞-32

According to the meaning of the question: 2x + 33 ≥ 0, sort out: 2x ≥ - 3, solution: X ≥ - 32
Given that the negative solutions of the inequality 2x + a > = 0 are exactly - 3, - 2, - 1, we can find the value range of A
2x+a>=0
2x>=-a
x>=-a/2
∵ negative integer solutions are exactly - 3, - 2, - 1
∴-4
2x﹣a＞0
2x>a
x>a/2
Because there are exactly negative integer solutions - 4, - 3, - 2, - 1,
So: - 5 ≤ A / 2 < - 4
-10≤aa
x>a/2
Because there are exactly negative integer solutions - 3, - 2, - 1,
So: - 4 ≤ A / 2 < - 3
-8≤aa
x>a/2
Because there are exactly negative integer solutions - 4, - 3, - 2, - 1,
So: - 5 ≤ A / 2 < - 4
-10≤a
In the plane rectangular coordinate system, if the distance between point P and origin o is ρ, and the angle between OP and the positive direction of X axis is α, then [ρ, α] is used to represent the polar coordinates of point P. obviously, there is a one-to-one correspondence between the coordinates of point P and its polar coordinates. For example, the polar coordinates of point P (1,1) are p [radical 2,45 °]. If the polar coordinates of point q are (2 radical 2.20 °), then the coordinates of point q are?
In the plane rectangular coordinate system, let the distance from point P to origin o be ρ, and the angle between OP and the positive direction of X axis be α, then [ρ, α] is used to represent the polar coordinates of point P. obviously, there is a one-to-one correspondence between the coordinates of point P and its polar coordinates. For example, the polar coordinates of point P (1,1) are p [radical 2,45 °]. If the polar coordinates of point q are (2
Let plane coordinates (x, y) and polar coordinates (ρ, α)
p^2=x^2+y^2,tanα=x/y
There is y = (2 radical sign 2) sin20 degree
X = (2 radical 2) cos20 degree
(1 + x) n = A0 + a1x + a2x2 + a3x3 + --- + anxn, then the value of Ao + A1 + A2 + a3 + --- An is equal to
2^n
EF is the median line of the triangle ABC, the bisector of the external angle ACG intersects the straight line EF at point D, and proves that ad is perpendicular to CD
∵ EF is the median line of triangle ABC
And AF = FC
∴∠FDC=∠DCG
And ∵ ∠ FCD = ∠ DCG
∴∠FDC=∠FCD
∴FD=FC
And ∵ AF = FC
∴AF=FC=CD
A triangle ADC is a right triangle (according to the inverse theorem that the center line on the hypotenuse of a right triangle is equal to half the length of the hypotenuse)
That is: ad ⊥ CD
If the polynomial - 3x ^ A - (b-2) x + 4 is a quadratic binomial, then a =? B =?
Quadratic binomial, the highest order is 2, and the expression has only two terms
So a = 2, B-2 = 0, B = 2,
A and B are both 2
A point moves in the plane rectangular coordinate system xoy according to the following rule. Starting from the origin P0 (0,0), it first moves 1 unit to the right to point P1, then 1 unit to point P2, then 2 units to point P3, then 2 units to point P4, then 3 units to point P5, then 3 units to point P6, and then 4 units to point P7, And then down 4 units to point P8,..., according to this rule, what is the coordinate of point P100
P8(-2,-2)
P100(-25,-25)
P1(1,0),P2(1,1),P3(-1,1),P4(-1,-1),P5(2,-1),P6(2,2),P7(-2,2),P8(-2,-2).
From the above rule, we can see that the coordinates of the nth point (n is a multiple of 4) (- N / 4, - N / 4), so P100 (- 25, - 25)
Given that A1 ≥ A2 ≥... ≥ an > 0, x1, X2, X3,..., xn is an permutation of A1, A2,..., an, prove: X1 / A1 + x2/
Given that A1 ≥ A2 ≥... ≥ an > 0, x1, X2, X3,..., xn is a permutation of A1, A2,..., an, prove: X1 / A1 + x2 / A2 +... + xn / an ≥ n, use the ranking inequality!
Let a {a 2 +... (a 2 / a 2 / an)} be a {a 2 +... (a 2 / a 2 / an)}
In triangle ABC, EF is the median line of triangle ABC, ad is the median line of BC, what is the relationship between AD and ef? To process, good!
Ad and EF are equally divided
Reason: connect de and DF
∵ EF is the median of △ ABC, ad is the median of BC
E, F and D are the middle points of the three sides, that is, de and DF are the median lines of the triangle
∴DE‖AC,DF‖AB
The quad AEDF is a parallelogram
The ad and EF are equally divided
It is known that in the (x + 33x) n expansion, the ratio of the sum of the coefficients to the sum of the binomial coefficients is 64, then n is equal to______ .
According to the properties of binomial coefficients, in the (x + 33x) n expansion, the sum of all binomial coefficients is 2n. In (x + 33x) n, let x = 1, then (1 + 3) n = 4N, then the sum of all coefficients is 4N. According to the meaning of the problem, 4n2n = 64, the solution can get n = 6; so the answer is 6