Will 12345 and addition, subtraction, multiplication and division each use once, equal to 22? According to the simplest elementary school algorithm

Will 12345 and addition, subtraction, multiplication and division each use once, equal to 22? According to the simplest elementary school algorithm

[(5-1)+(3/2)]*4=22
Try any one
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4 * 5 + 3 + 1-2 = 22 question: where did your multiplication go
Let the sum of the first n terms of the arithmetic sequence be Sn, A3 = 24, S11 = 0
Let the sum of the first n terms of the arithmetic sequence {an} be Sn, A3 = 24, S11 = 0
Finding the general formula of {an} series
2 find the first n terms and Sn of sequence {an}
When the value of n is, Sn is the maximum, and the maximum value of Sn is obtained
The arithmetic sequence an = P * (n-1) + A1, Sn = (a1 + an) * n / 2 = n * a1 + p * (n-1) * n / 2A3 = 2 * P + A1 = 24, S11 = 11 * a1 + 55 * P = 0, A1 = 40, P = - 8 (1) an = - 8N + 48 (2) Sn = - 4N (n-1) + 40n (3) let an = 0, n = 6, so when n = 5 or 6, there is the maximum value Sn = 120
Unit conversion of nanometer?
What is the step-by-step unit conversion from 1 nanometer (nm) to 1 meter (m)?
1nm = 0.001 μ M = 0.000001 mm = 0.0000001cm = 0.00000001 decimeter = 0.000000001 meter
1nm=10^(-9)m
1nm=0.000001mm=0.0000001cm=0.000000001m
001 km = 0.01 M = 0.1 decimeter = 1 cm = 10 mm = 100 SM = 1000 HM = 10000 μ M = 10000000 NM
10-3 km = 1 m = 10 decimeter = 100 cm = 1000 mm = 106 μ M = 109 NM
12345 use addition, subtraction, multiplication and division for each sample only once, and the result is 22
（3÷2－1+5）×4=22
5*4=20 20+3-2+1=22
3-2 1 4X5=22
3X5 2X4-1=22
3X4 2X5X1=22
Let the sum of the first n terms of the arithmetic sequence an be Sn, A3 = 24, S11 = 0. If BN = | an |, find the sum of the first 50 terms of the sequence BN
If S11 = [11 (a1 + a11)] / 2 = 0, then: a1 + a11 = 0, because 2A6 = a1 + a11 = 0, then: A6 = 0, because A3 = 24, then: a6-a3 = 3D, then: D = - 8, then: an = - 8N + 48, then: SN = [n (a1 + an)] / 2 = n (44-4n), then: S50 = - 7800, S6 = 120, the sum of the first 50 terms of sequence {BN} is t, then: T = | A1 | + | A2 |
a3=a1+2d=24、a1=24-2d
S11=11a1+55d=0、a1=-5d
24-2d=-5d、d=-8、a1=40
an=40-8(n-1)=-8n+48
Let an = - 8N + 48 = 0, then n = 6.
a1=40、a2=32、a3=24、a4=16、a5=8、a6=0
a7=-8、a8=-16、… 、a50=-352
b1+b2+… +b50=40+32+24+16+8+0+8+16+… +352=5*(40+8)/2+44*(8+352)/2=8040
If the tolerance is D and the first item is A1, then A3 = a1 + 2D = 24, S11 = A1 * 11 + 1 / 2 * 11 * 10 * d = 0
Then A1 = 40, d = - 8
Then an = 40-8 (n-1) Sn = 40n + 1 / 2 * n * (n-1) * - 8) S6 = 120
b50=-(S50-S11-S6)= 8040
eight thousand and forty
The first term A1 = 40, tolerance d = - 8, A6 = 0 can be obtained from A3 = 24, S11 = 0 of the arithmetic sequence, so the sum of the first 50 terms of BN is T50 = - S50 + 2, S6 = 8040
I wonder if it solved your problem?
S11=11a6=0
So A6 = 0
Because A6 = A3 + 3D = 24 + 3D = 0
So d = - 8
an=48-8n
48-8n (n ≤ 6)
bn= {
8n-48(n>6)
Let tn be the sum of the first n terms, then 44n-4n ^ 2 (n is less than or equal to 6)
... unfold
S11=11a6=0
So A6 = 0
Because A6 = A3 + 3D = 24 + 3D = 0
So d = - 8
an=48-8n
48-8n (n ≤ 6)
bn= {
8n-48(n>6)
Let tn be the sum of the first n terms, then 44n-4n ^ 2 (n is less than or equal to 6)
Tn=
4n^2-44n+240(n>6)
T50 = 8040 * Stow
High school physics conversion of all units, such as nano and micro meters
1m=10dm=100cm=1000mm=1000000um=1000000000nm
Millisecond is 10 ^ - 3, 1 mm = 10 ^ - 3 m
Micro is 10 ^ - 6,
Na is 10 ^ - 9
Do you have any other units besides the length
1 2 3 4 5 6 7 8 9 = 99 add subtract multiply divide in the blank
This question is very simple, the final answer is 99, that is 1 to 8 to 90, so there are many ways
For example: (1 + 2-3) * 4 * 5 + 6 * (7 + 8) + 9 = 99, etc
There's not only one way. You can come up with other answers. Come on!
1*(2+3-4+5+6+7-8)*9=99
1+2-3+4+5+（7-6）+89=99
1*(2+3-4+5+6+7-8)*9=99
(1 + 2-3) * 4 * 5 + 6 * (7 + 8) + 9 = 99, etc.
Let the sum of the first n terms of the arithmetic sequence {an} be Sn, given A3 = 24, S11 = O, find the general term formula 2 of a sequence {an} when m is the sum value, Sn is the maximum, and the maximum value is
Because a1 + a11 = A3 + A9
So S11 = (a1 + a11) * 11 / 2 = (A3 + A9) * 11 / 2 = (24 + A9) * 11 / 2 = 0
So A9 = - 24
So d = (a9-a3) / 6 = - 8
a1=a3-2d=24+16=40
So an = 40-8 (n-1) = - 8N + 48
an=-8n+48>=0
The solution is n
One
S11=(A1+A11)×11/2=(A3+A9)×11/2=0
A3+A9=0
A9=-A3=-24
6d=A9-A3=-24-24=-48
d=-8
A1=A3-2d=24-2×(-8)=40
An=A1+(n-1)d=40+(n-1)×(-8)=48-8n
Two
D
What is the unit conversion between inch and ruler and meter?
1 meter = 3 feet = 30 inches
9 8 7 6 5 4 3 2 if the position is not changed, add, subtract, multiply and divide by brackets to get 1000
987+65/(4+3-2)=1000
987-6+5*4-3+2=1000
987-6+5+4*3+2=1000
987+6+5-4+3*2=1000