Unit conversion (pound, Newton, inch, centimeter) There is one category: it has a tear force standard of 57 pounds per inch Now the result of my measurement: 159 n / cm Excuse me: can I pass the standard test? Is it 57 lb / in or 159 n / cm? Copy the party, please respect yourself!

Unit conversion (pound, Newton, inch, centimeter) There is one category: it has a tear force standard of 57 pounds per inch Now the result of my measurement: 159 n / cm Excuse me: can I pass the standard test? Is it 57 lb / in or 159 n / cm? Copy the party, please respect yourself!

57 lb / in large = 99.76 n / cm
don't worry
One pound equals 0.45359237 kg,
1 inch = 2.5399918 cm (CM),
57 lb / in = (57 LB * 0.45359237 kg / lb * 9.8 N / kg) / (2.539999918 cm)
=99.75460868577871 n / cm < 159 n / cm
So the owner's items can pass the test
1 Newton = 0.225 LBF,
1 cm = 0.394 in,
159 n / cm
＝159*0.225/0.394
= 90.8 > 57 PSI
This item can pass the standard test.
Unit conversion can be so calculated, you can find a simple you will try.
An elementary school sixth grade score application question, the formula also wants!
The cucumbers in the experimental field have a good harvest. Class 6 (1) has collected 3 / 8 of all the cucumbers, which is 36 kg more than 4 baskets full; class 6 (2) has collected the rest, which is just 8 baskets full
(1) How many parts of the whole cucumber is a basket of cucumbers?
(2) How many kilos of cucumbers are collected?
*Note: the score is as follows: one third is 1 / 3, five eighths is 5 / 8
(1)(1-3/8)÷8=5/64
(2) 36 ÷ (3 / 8-5 / 64 × 4) = 576 (kg)
Let the sum of the first n terms of the arithmetic sequence an be Sn, where a1 = 3, s5-s2 = 27
[answer] an = 2n + 1
[analysis]
s5-s2=a3+a4+a5=3·a4=27
So, A4 = 9, d = (9-3) △ 3 = 2
an=3+（n-1）·2=2n+1
Twenty years of teaching experience, professional trustworthy!
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an=2n+1
S6=6a1+6*5d=6a1+30d
S2=2a1+2*1d=2a1+2d
6a1+30d-2a1-2d=4a1+28d=40
a1+7d=10
d=(10-3)/7=1
an=a1+(n-1)d=3+(n-1)*1=n+2
Thank you
1. The correct conversion of the following length units is ()
Although I know the conversion rate, I don't know which one is correct for the following length units ()
A．0.96 nm＝0.96×10－3μm=9.6×10－4μm B．9.6 cm＝9.6÷100＝0.096 m
C．9.6 cm＝9.6 cm×10 mm＝96 mm D．96 cm＝9.6 cm×10＝96 mm
The answer is a
-------------------------------------
Explanation:
The formula used in a: 1 nm = 0.001 & # 181; m = 1x10 ^ - 3 & # 181; m
0.96 nm = 0.96 x 10 ^ - 3 & # 181; m = 9.6 x 10 ^ - 4 & # 181; m (so a is correct)
The formula used in B is 1 cm = 0.001 M
9.6 cm = 9.6 x 0.001M = 0.0096 m (so B is wrong)
The formula used for C is 1 cm = 10 mm
9.6 cm = 9.6 x 10 mm = 96 mm
The formula used for D is 1 cm = 10 mm
96 cm = 96 x 10 mm = 960 mm
Don't jump to a conclusion
Please look for the next mathematics problem (the content is factorization and fraction of the addition, subtraction, multiplication and division) thank you~
1. Extract the common factor
12x square - 12x square Y - 3x square y square
2. Square difference formula
3ax quartic-3ay quartic
3. Complete square formula
25mm2 + 64-80m
4. Group decomposition
3xy-2x-12y+8
5. Cross multiplication
X fourth power - 7x square y square + 6y fourth power
The formula is as follows
Add and subtract 5x / (x + y) + Y / (x + y)
Multiplication and Division B / (square-9) * (a + 3) / (square-b)
Mixed braces a / (a-b) + B / (B-A) braces * AB / (a-b)
Let the sum of the first n terms of the arithmetic sequence {an} be Sn, if A1 = 2 + T, s5-s2 = 24 + 3T (T > 0). (I) find the general formula of the sequence {an}; (II) let BN = aqn + N, if B1 = A1, B5 = A5, try to compare the size of A3 and B3
(1) Let the tolerance of the arithmetic sequence {an} be D, then s5-s2 = 3A1 + 9D = 24 + 3T If A1 = 2 + T, then d = 2 So an = 2n + t (6 points) (II) AQ = 1 + T > 0, aq5 = 5 + T (8 points) add up to 3 + T = 12 (AQ + aq5) (10 points) aq5 AQ = AQ (Q
Unit conversion in Physics: kW · h and j
1KwH=1000W*3600s=3600000J =3.6*10^6J
1000*3600J
1 kwh is equal to the sixth power J of 3.6 * 10
1:3.6 times the octave of 10
The more, the better
There are 30 colored papers in the school, 11 for paper flowers and 9 for small flags. How many are left?
There are 85 books in the small bookcase, 32 in the morning and 26 in the afternoon. How many are left?
3. The food store has 95 bottles of soda, 36 in the morning and 45 in the afternoon. How many bottles are left?
Mr. Wang spent 48 yuan on harmonica, 36 yuan on flute and 100 yuan on salesgirl. How much should he get back?
5. The clothing store transported 200 meters of cloth, 54 meters for children and 46 meters for baby clothes. How many meters are left?
There are 80 boxes of chalk in the school. 18 boxes are used in the first day and 26 boxes are used in the second day. How many boxes are left?
There are 40 red schoolbags and 50 blue schoolbags in 7 stores. They sell 37. How many are left?
8 the students made 20 clay figurines, the teacher made 8 clay figurines. 25 clay figurines were given to the kindergarten. How many clay figurines are left?
9. There are 14 boxes of chalk in the school and 30 boxes bought. How many boxes of chalk are there now?
There were 40 boxes of chalk in the school, 26 boxes were used and 30 boxes were bought. How many boxes of chalk are there now?
I can't find it easily. I hope I can help you
It is known that the sum of the first n terms of the arithmetic sequence {an} is Sn, and A1 = 2, S5 = 30
It is known that the sum of the first n terms of the arithmetic sequence {an} is Sn, and A1 = 2, S5 = 30 (1) the general term formula of the arithmetic sequence {an} (2) if the sequence {BN} satisfies the an-1 power of BN = 2, the sum of the first n terms of the arithmetic sequence {BN} is TN (3) if the sequence {CN} satisfies CN = 1 / Sn, the sum of the first n terms of the arithmetic sequence {CN} is RN
(1)
an=a1+(n-1)d= 2+(n-1)d
S5 = (2+2d)5 = 30
D=2
an = 2+(n-1)2 = 2n
(2)
bn=2^(an-1)
= 2^(2n-1)
Tn =b1+b2+...+bn
= 2(2^(2n) -1) / (4-1)
= (2/3)(2^(2n) -1)
(3)
cn =1/Sn
= 1/ [n(n+1)]
= 1/n -1/(n+1)
Rn = c1+c2+...+cn
= 1-1/(n+1)
= n/(n+1)
Electric work and electric heating
The electric iron will be very hot after being electrified for a period of time, but the wire connecting the electric iron is not too hot. This is because the wire () is small, and the current through the wire () is too small
Because the resistance of the wire is small, the current through the wire does too little work
The electric iron will be very hot after being electrified for a period of time, but the wire connecting the electric iron is not too hot, because the (resistance) of the wire is small, and the (heat generation) of the current through the wire is too small.
If it helps, please take it
(*^__ ^*(hee hee Thermogenesis?? O(∩_ ∩) O ~ yeah
According to Joule's law
If it helps, please take it
To begin with
The electric iron will be very hot after being electrified for a period of time, but the wire connecting the electric iron is not too hot, because the (resistance) of the wire is small, and the (heat generation) of the current through the wire is too small.
If it helps, please take it
(*^__ ^*(hee hee Follow up: heat production?? O(∩_ ∩)O~