An is an equal ratio sequence, A3 + A6 = 36, A4 + A7 = 18, find A1 and Q

An is an equal ratio sequence, A3 + A6 = 36, A4 + A7 = 18, find A1 and Q

(q=0.5
a1=128)
A3 + A6 = 36 (formula 1)
Q (A3 + A6) = 18, so q = 0.5
Bring in Formula 1
a1*q^2(1+q^3)=36
A1 = 128
A number is not only a factor of 32, but also a multiple of 8______ .
Because the multiples of 8 are: 8, 16, 24, 32 And the biggest factor of 32 is itself, so it is not only the factor of 32, but also the multiple of 8. The biggest number is 32
Each bottle of drink is 3 yuan, buy 5 get 15 free, 45 students each bottle, how much does it cost, how many bottles?
45 yuan, 15 bottles
In known equal ratio sequence {an}, A3 + A6 = 36, A4 + A7 = 18, an = 12, find n
Let the common ratio of the equal ratio sequence {an} be q, because A3 + A6 = 36, ① A4 + A7 = 18 & nbsp; & nbsp; ②, ② ① can get A4 + a7a3 + A6 = q = 12, so A3 + A6 = a1q2 + a1q5 = 14a1 + 132a1 = 36, the solution is A1 = 27, so the general formula an = 27 × (12) n − 1 = 28-n, let 28-n = 12 = 2-1, the solution is n = 9
A number is not only a multiple of 9, but also a multiple of 72______ .
Because 9 = 3 × 3, 72 = 3 × 3 × 2 × 2 × 2, the least common multiple of 9 and 72 is: 2 × 2 × 2 × 3 × 3 = 72, so the answer is: 72
There are 52 people in class 4.1. They buy four boxes just one box for each. How many boxes of drinks are there in each box?
(52-4) △ 4 = 48 △ 4 = 12 (boxes); answer: there are 12 boxes in each box
In {an}, A3 + A5 = 18, A9 + a11 = 144, then A5 + A8 = 144___ .
A3 + A5 = 18, A9 + a11 = 144, then a1q2 (1 + Q2) = 18; a1q8 (1 + Q2) = 144.. Q6 = 8.. Q2 = 2 {q = 2, q = - 2. So A1 = 3. When q = 2, so A5 + A8 = a1q4 (1 + Q3) = 12 (1 + 22). When q = - 2, A5 + A8 = a1q4 (1 + Q3) = 12 (1-22)
The largest factor of a number is 16, and the smallest multiple of the number is______ .
The largest factor of a number is 16, and the smallest multiple of the number is 16
Two for hamburgers, three for sausages and one for drinks
There are 12 children going on a spring outing. If each of them buys two hamburgers, a sausage and a bottle of drink, how can they buy the right one
Hamburg 12 * 2 / (2 + 1) * 2 = 16
Sausage 12 / (3 + 1) * 3 = 9
Beverage 12 / (1 + 1) = 6 bottles
12 divided by 3 times 2 = 8 buy eight hamburgers
12 divided by 4 times 3 = 9 buy nine sausages
12 divided by 2 times 1 = 6 buy six drinks
Buy 8 hamburgers, that is 8 / 2 = 4. Give 4 hamburgers, that is 8 + 4 = 12 (hamburgers).
Buy 9 sausages, that is 9 / 3 = 3. Send 3 sausages, that is 3 + 9 = 12 sausages.
Buy 6 bottles of drinks, that is 6 / 1 = 6. Send 6 sausages, that is 6 + 6 = 12 (bottles) drinks.
The above is just my answer and analysis
16 hamburgers, 9 sausages, 6 bottles of drinks!
If A2 + a3 = 1, A4 + A5 = 2, then A8 + A9 equals ()
A. 22B. 4C. 8D. 16
Let the common ratio of the equal ratio sequence {an} be q, then Q2 = A4 + a5a2 + a3 = 2, so A8 + A9 = (A4 + A5) Q4 = 2 × 22 = 8, so C is chosen