It costs 26 yuan to buy two snacks and one drink. It costs 18 yuan to buy one snack and three drinks. How much does it cost for one snack and one drink? Don't use equations, use formulas

It costs 26 yuan to buy two snacks and one drink. It costs 18 yuan to buy one snack and three drinks. How much does it cost for one snack and one drink? Don't use equations, use formulas

(18 * 2-26) divided by 5 = 2 (yuan) this is the first 18 * 2 to get two snacks, six drinks, minus 26, the remaining five drinks, divided by 5, get a cup
(26-2) divided by 2 = 12 (yuan), there's no need to explain~
If a1 + A2 = 40, A3 + A4 = 60, then A7 + A8=______ .
The answer is: a = 40 + 135, a = 40 + 60, a = 40 + 135
How much is zero minus one?
Zhengyi
One
One
0-(-1)=1
Um.
100+99-98+97-96+… +3-2+1=______ .
100+99-98+97-96+… +3-2+1，=100+1+（99-98）+（97-96）+… +(5-4) + (3-2), = 101 + 1 × (100-2) △ 2, = 101 + 49, = 150
Let 1 = A1 ≤ A2 ≤ Where a1, A3, A5 and A7 are equal ratio sequences with common ratio Q and A2, A4 and A6 are equal difference sequences with tolerance 1, then the minimum value of Q is ()
A. 33B. 1C. 3D. 3
∵1=a1≤a2≤… The minimum value of A6 is 3, the minimum value of A7 is 3, A1 = 1, and A1, A3, A5 and A7 are equal ratio sequences with common ratio Q. there must be Q > 0, a7 = a1q3 ≥ 3, Q3 ≥ 3, and the minimum value of Q is 33
The absolute value of minus 4 minus (minus 5) is ()
-4-(-5)=-4+5=1
Absolute or 1
One
One
|-4-（-5）|
=|-4+5|
=|-1|
=1
100—99+98—97+96—~~~~~~+2—1=( )
100—99+98—97+96—~+2—1
=(100—99)+(98—97)+(96—~+(2—1)
=50
Fifty
In the arithmetic sequence {an}, if the tolerance D ≠ 0 and A1, A3 and A7 are equal proportion sequence, then a1 + a3a2 + A4=______ .
So we can get the answer from a1 + 2 D = a1 + 2 D = a1 + 2 D = a1 + 2 D = a1 + 2 d
The difference between the product of two internal terms minus the product of two external terms in a proportion is zero______ (judge right or wrong)
Because in proportion, the product of two internal terms equals the product of two external terms, so the difference between the product of two internal terms and the product of two external terms is 0
100m3-99m3 + 98m3-97m3 + ····· + 2m3-1
It's better to use words, but not numbers
The factorization can be (100 + 99) (100-99). Similarly, the original formula is equal to adding 100 to 1, and the result is (100 + 1) × 100 △ 2 = 5050