There are four ninth out of four math problems in the fifth grade of primary school, so what are there seven in two seventh

There are four ninth out of four math problems in the fifth grade of primary school, so what are there seven in two seventh

two-forty-ninths
one-seventh
Four ninths out of four ninths, then seven halves out of two sevens
Little Man
2/49…… There are seven 49 / 2
2 / 7 of 7 = 2 / 49
Fill in 1, 2, 3, 4, 5, 6, 7, 8 and 9 in () to form three formulas. Each number can only be used once
First: (2) * (3) = (6)
( 7)+( 1)=(8 )
( 4)+(5 )=(9 )
The second: (6) / (2) = (3)
(5 )+(4 )=(9 )
(7 )+(1)=(8 )
The third: (9) - (4) = (5)
(2 )*( 3)=(6 )
( 8)-(1 )=(7 )
and so on
For a story book, Xiao Hong read 3 / 8 of the whole book on the first day, 3 / 10 of the whole book on the second day, and finished it on the third day
How many parts of this book did you read on the third day?
1-3/8-3/10
=5/8-3/10
=25/40-12/40
=13/40
A: I read 13 out of 40 books
-1 / 2, 2 / 3, - 3 / 4, 4 / 5, - 5 / 6, 6 / 7 The ninth number is () and the 2001 number is ()
-9 out of 10 and - 2001 out of 2002
-9/10
-2001/2002
-9 / 10 and - 2001 / 2002
9 8 7 6 5 4 3 2 1 how to use addition, subtraction, multiplication and division to equal 22
9+8*7-6*5-4*3-2+1=22
[(9-8)-(7-6)]+5x4+3-2+1
9+8+7+6-5-4+3-2÷1=22
1*2+3-4+5+6-7+8+9
(9+8-7)*6/5+4+3*2*1
It took Xiao Hong three days to finish reading a story book. On the first day, she read 3 / 1 of the whole book, and on the second day, she read the remaining 5 / 2. It is known that she read 24 times less on the second day than on the third day
How many pages does the story book come to?
A total of 180 pages, the solution is, let this book have y pages, the third day I read x pages, then 1 / 3Y + 2 / 3Y * 2 / 5 + x = y, 2 / 3Y * 2 / 5 + 24 = X
Y = 180, x = 72
Let the whole book be X,,
One third x on the first day
The next day, 2 / 3 x multiplied by 2 / 5
On the third day, 2 / 3 x times 2 / 5 + 24
Format 3 / x + (3 / 2x * 5 / 2) + (3 / 2x * 5 / 2 + 24) = x conversion, multiply all by 15 to remove fractions
5X+4X+4X+360=15X
... unfold
Let the whole book be X,,
One third x on the first day
The next day, 2 / 3 x multiplied by 2 / 5
On the third day, 2 / 3 x times 2 / 5 + 24
Format 3 / x + (3 / 2x * 5 / 2) + (3 / 2x * 5 / 2 + 24) = x conversion, multiply all by 15 to remove fractions
5X+4X+4X+360=15X
2X = 360
X = 180 ° Stow
(cycle of 3.22 + cycle of 1.33 + cycle of 4.66 + cycle of 2.44) divided by one third, the process and result are calculated
(cycle of 3.2 2 + cycle of 1.3 3 + cycle of 4.6 6 + cycle of 2.4 4) divided by one third,
=(3 2 / 9 + 1 1 / 3 + 4 2 / 3 + 2 4 / 9) × 3
=11 2 / 3 × 3
=33+2
=35
That's all
(3.2 2 cycles + 1.3 3 cycles + 4.6 6 cycles + 2.4 4 cycles) divided by one third
=(3 + 2 / 9 + 1 + 1 / 3 + 4 + 2 / 3 + 2 + 4 / 9) △ 1 / 3
=11 and 2 / 3 △ 1 / 3
=35
22 cycle = 2 / 9, 0.33 cycle = 3 / 9, 0.44 cycle = 4 / 9; 0.66 cycle = 6 / 9,
2 / 9 + 3 / 9 + 6 / 9 + 4 / 9 + 3 + 1 + 4 + 2 = 10 + 15 / 9 original question = (10 + 15 / 9) X3 = 30 + 5 = 35
It's the sum of 1 and 2 / 9 plus 1 and 3 / 1 plus 4 and 3 / 2 plus 2 and 9 / 4, divided by 1 / 3, and finally it's 35
Six four's plus, minus, multiply and divide equal five and seven and eight and nine and ten
(4+4+4+4+4)÷4=5
(4×4+4+4+4)÷4=7
4×4+4-4-4-4=8
4+4+(4+4-4)÷4=9
(4×4+4+4)÷4+4=10
(4+4+4+4+4)/4=5
(4+4)-4/4-4/4=6
(4*4+4+4+4)/4=7
4+4+4+4-4-4=8
4/4+4+4+4-4=9
4/4+4/4+4+4=10
4+4-(4+4+4)/4=5
4*4/4+4-4/4=7
4*4*4/4/4+4=8
4*4/4+4+4/4=9
4+4+4/4+4/4=10
A story book read two fifths of the first day, read the remaining quarter the second day, and read what percentage of the whole book the next day?
I read two fifths of a story book on the first day, the remaining quarter on the second day, and what percentage of the whole book on the second day?
(1-2/5)×1/4
=3/5×1/4
=3/20
A new operation: a × B = 1 / A + 1 / B, then 1 × 2=
If a × B = 1 / A + 1 / B, then 1 × 2 = 1 / 1 + 1 / 2 = 3 / 2 = 1.5
1X2=1/1+1/2=3/2
It's 3 / 2.
=1+1/2=3/2
=1/1 1/2=3/2
1×2=1/1+1/2=3/2=1.5
1+1/2=3/2
∵a×b=1/a+1/b,
∴1×2=1/1+1/2=2/2+1/2=3/2=1.5.