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1. Xiaoming bought 160 orange trees and peach trees at 36 yuan, 0.2 yuan for each peach tree and 0.3 yuan for each orange tree. How many of these two kinds of saplings did he buy 2. There are 48 heads and 152 feet in the same cage. How many chickens and rabbits are there? (equation calculation) 3. The sum of the ages of father and son this year is 35. In five years, the age of son is 25% of that of father. What are the ages of father and son this year? (equation calculation) 4. A factory plans to produce a batch of electric fans. If it produces 50 fans per day, it will be completed on schedule. If it produces 60 fans per day, it will be completed five days in advance. How many fans are planned to produce? (calculate by equation) 2、 Fill in the blanks below: 1. The sum of a and B is 72, the number a is three fifths of B, the number a is (), the number B is () 2. The oil yield of soybean is 17%. The oil factory plans to squeeze 0.51 tons of soybean. How many tons of soybean are needed?
1. Set X orange seedlings and Y peach seedlings
x+y=160
0.3x+0.2y=36
The solution is x = 40, y = 120
2. Set X chickens and Y rabbits
A chicken has one head and two feet; a rabbit has one head and four feet
x+y=48
2x+4y=152
The solution is x = 20, y = 28
3. The father is x years old and the son is y years old
x+y=35
y+5=25%(5+x) 25%=0.25
The solution is x = 31, y = 4
4. Plan to produce y fans in X days
50x=y
60（x-5)=y
The solution is x = 30, y = 1500
2
The number a is 27 and the number B is 45
Let a be x and B be y
x+y=72
3/5y=x
2. The title seems to have two wrong words
We need three tons of soybeans
Let x = 17.51 tons
How many times 12 is 120
Ten
Xiao Ming read a story book. On the first day, he read a quarter of the whole book. On the second day, he read a fifth of the whole book. If there are 11 pages left, how many pages are there?
11 / (1-1 / 4-1 / 5) = 20 (page)
1. (1.995 + 3.335 + 9.115) / (1.991 + 3.331 + 9.111)=
(1.995 + 3.335 + 9.115) / (1.991 + 3.331 + 9.111)
=(104/99+104/33+104/5)/(100/9+100/33+100/11)
=104*(1/99+1/33+1/11)/[100*(1/99+1/33+1/11)]
=104/100
=26/25
three hundred and thirty-eight-325ths
A ten digit number containing ten digits of 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 is called a "perfect number". If a "perfect number" satisfies the following requirements: (1) it can be divisible by 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12 respectively; (2) its sum with 2004 can be divisible by 13; then what is the smallest of such "perfect numbers"___ .
1. Because 0 + 1 + 2 + +8 + 9 = 45, so the arrangement of any ten numbers can be divided by 3 and 9; 2. Secondly, the number should be divisible by 2, 5 and 10, so the last digit must be 0; 3. Because this number is required to be the smallest, the small number should be put in the front, the large number should be put in the back as far as possible, assuming that the first four digits are 1234; 4. Because this number can be divided by 8, the penultimate digit should be even, and as large as possible, take 8; similarly, the reciprocal number The third digit is 6; to sum up, this number is 1234 680, the number satisfying this form must be 1, 2, 3, 4, 5, 6, 8 and 9; now fill in the space of 5, 7 and 9 to make it divisible by 7, and the minimum can be. Through the test, 1234759680 can be divisible by 11 and 12. Therefore, the minimum of such "perfect number" is 1234759680. So the answer is: 1234759680
one hundred and sixty-six thousand three hundred and twenty
one hundred and sixty-six thousand three hundred and twenty
Xiao Ming read a story book. On the first day, he read a quarter of the whole book. On the second day, he read a fifth of the whole book. If he read 18 pages in two days, how many pages?
18 divided by (quarter + Fifth) = 40 (page)
How can 9.99 * 2.22 + 3.33 * 3.34 be easily calculated?
9.99*2.22+3.33*3.34
=3.33*3*2.22+3.33*3.34
=3.33*(6.66+3.34)
=3.33*10
=33.3
1 / 2, 1 / 3, 1 / 10, 1 / 15, 1 / 26, () according to the rule, what numbers should be filled in the brackets
2=1*1+1
3=2*2-1
10=3*3+1
15=4*4-1
26=5*5+1
35=6*6-1
The back is 1 / 35
I agree with Wang Tianyang
The rule is that the denominator is the square of N + (- 1) and the N + 1 power of the numerator is 1, so n = 6 should be 1 / 35
The last answer is very good. I think this kind of question can be simplified: directly put forward the denominator separately to form a sequence of numbers, 2,3,10,15,26, () later, we can also consider this when we solve it
How many pages of the book did you read in the second day?
The road repair team has transported 12 trucks of sand and soil, with an average weight of 5.5 tons per truck. After 7 days, there are still 3 tons left. How many tons do they use per day?
15/(30%-1/4)
=15/5%
=15/0.05
==300 pages
The book has 300 pages
（5.5*12-3）/7
=(66-3)/7
=63/7
=9 tons
The average daily consumption is 9 tons
Total = 15 (0.3-0.25) = 300 pages;
Daily = (12 × 5.5-3) △ 7 = 63 △ 7 = 9 tons;
If you don't understand this question, you can ask. If you are satisfied, remember to adopt it
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I wish you progress in your study
Xiao Ming read a story book. On the first day, he read 1 / 4 of the whole book. On the second day, he read 30% of the whole book. On the second day, he read 15 more pages than on the first day. This book has 240 Pages
12/( 30%- 1/4) = 12/ 5% = 240
The road repair team transported 12 trucks of sand and soil, with an average weight of 5.5 tons. After seven days, there were still 3 tons left, with an average of 9 tons per day
(12x5.5 -3) / 7 = 9
Simple operation of 1 + 3 + 5 + 7 up to 99
First, divide the formula for the number of terms (the last term minus the first term) by the tolerance plus 1, that is, (99-1) divided by (3-1) + 1 = 50, 50 is the number of terms
Then divide the number of multiplication terms by 2 in the equal difference test (the first item plus the last item) is (1 + 99) times 50 divided by 2 = 2500
Let me tell you a summation formula of tolerance sequence
(first item + last item) * number of items / 2
The first item is the first number, the last item is the last number, and the number of items is the total number of numbers, which can be calculated
(first item + last item) * number of items / 2
(1+99)*50/2=2500
(1+99)*50/2=2500
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