It is known that M is the sum of all integers a satisfying the inequality root 3 < a < root 6, and N is the largest integer solution satisfying the inequality x ≤ 2 / 2 of the root sign 37-2

It is known that M is the sum of all integers a satisfying the inequality root 3 < a < root 6, and N is the largest integer solution satisfying the inequality x ≤ 2 / 2 of the root sign 37-2

M is the sum of all integers a satisfying the inequality - radical 3 < a < radical 6. A has - 1, 0, 1, 2, M = 2
N is the largest integer solution satisfying the inequality x ≤ 2 / 2 root sign 37-2. If the root number 37 is regarded as the root sign 36, it is easy to get n = 1
m+n=3

Satisfy the inequality 4 / radical 3 + radical 2

4 / (root 3 + root 2) < x < 4 / (root 5-root 3)
4 root number 3-4 root number 2 < x < 2 root number 5 + 2 root number 3
Decimals
1.27＜x＜7.94
X has 2, 3, 4, 5, 6, 7

What is the solution set of X-1 > x-3 under the root of inequality

X-1 > x-3 under radical
X-1 > = 0, x > = 1
(1) When x > = 3: x-3 > = 0
The square of two sides is: X-1 > x ^ 2-6x + 9
x^2-7x+10

The solution set of the inequality Tana + (3 under radical) / 3 > 0 is Why K π? Not K2 π

Tana + (root 3) / 3 > 0
Tana > - (root 3) / 3
In the Tana region (- π / 2, π / 2), - π / 6

Solving the root of inequality x > X-1 by image The best way to have a picture, I also know that the key is the solution

（(3-√5)/2,(3+√5)/2)

Solving inequality: under root sign (2x-3) (x + 1)

(2x-3) (x + 1) > = 0, x > = 3 / 2 or x = 5 / 2]
So the solution is x > = 3 / 2
Solution set {x | x > = 3 / 2}

The inclination angle of the root of the line 3x-3y + 3 = 0 is?

Let x denote Y: y = x + 1 of 3 times the root of 3,
If the slope is 3 / 3, then Tana = 3 / 3
Then the angle a = 30 degrees
The inclination angle is 30 degrees

What is the inclination angle of the line 3x + radical 3y-6 = 0?

When it is converted into oblique section, 120 ° is obtained

It is known that the linear equation is If 3x + 3Y + 1 = 0, then the inclination angle of the line is______ .

∵ the linear equation is
3x + 3Y + 1 = 0, that is y=-
Three
3x-1
3, then the slope of the line is-
Three
Therefore, the tangent of the inclination angle is equal to 3-
Three
3，
Combined with the range of inclination angle, the inclination angle is 150 °,
So the answer is 150 degrees

What is the equation of the line passing through the intersection of the straight lines X + 3Y + 4 = 0 and 3x-2y + 1 = 0, and the distance from the origin is root 2

3x+9y+12=0
3x-2y+1=0
x=-1
y=-1
So the intersection point is (- 1, - 1)
1 'the slope of the line does not exist, and the line is x = - 1
The distance is 1
The slope of 2 'is K
Let the straight line be y + 1 = K (x + 1)
kx-y+k-1=0
Distance d = (see picture)
k=-1
The straight line is y = - X-1