As shown in the figure, a square ABCD with a side length a is connected inside the circle, and semicircles are made to the outside of the square with the diameter of each side of the square. Then, the area of the four crescent shaped by the four semicircles and the four arcs of the circumscribed circle of the square is______ .

As shown in the figure, a square ABCD with a side length a is connected inside the circle, and semicircles are made to the outside of the square with the diameter of each side of the square. Then, the area of the four crescent shaped by the four semicircles and the four arcs of the circumscribed circle of the square is______ .

According to the above analysis, the areas of the four crescent shapes are as follows:
4×1
2×π×(a
2)2+a2−1
2a2π，
=1
2a2π+a2-1
2a2π，
=a2．
So the answer is: A2

As shown in the figure, it is known that in ⊙ o, the diameter Mn = 10, the quadrilateral ABCD is a square, and ∠ POM = 45 °, then the length of AB is______ .

 POM = 45 °, DCO = 90 °, Doc = ∠ CDO = 45 °,  CDO is an isosceles right triangle,  co = CD. If OA is connected, then △ OAB is a right triangle, ∵ quadrilateral ABCD is a square,

As shown in the figure, we know that in ⊙ o, the diameter Mn = 10, the four vertices of square ABCD are on the radius OM, OP and ⊙ o respectively, and ᙽ POM = 45 °, then the length of AB is () A. 5 B. 4 C. 3 D. Five

∵ ABCD is a square,
∴∠DCO=90°，
∵∠POM=45°，
∴∠CDO=45°，
∴CD=CO，
∴BO=BC+CO=BC+CD，
∴BO=2AB，
Connect Ao,
∵MN=10，
∴AO=5，
In RT △ ABO,
AB2+BO2=AO2，
AB2+（2AB）2=52，
The result is: ab=
5，
Then the length of AB is
5．
Therefore, D

As shown in the figure, we know that in ⊙ o, the diameter Mn = 10, the four vertices of square ABCD are on the radius OM, OP and ⊙ o respectively, and ᙽ POM = 45 °, then the length of AB is () A. 5 B. 4 C. 3 D. Five

∵ ABCD is a square,
∴∠DCO=90°，
∵∠POM=45°，
∴∠CDO=45°，
∴CD=CO，
∴BO=BC+CO=BC+CD，
∴BO=2AB，
Connect Ao,
∵MN=10，
∴AO=5，
In RT △ ABO,
AB2+BO2=AO2，
AB2+（2AB）2=52，
The result is: ab=
5，
Then the length of AB is
5．
Therefore, D

As shown in the figure, we know that in the semicircle 0, the diameter Mn = 10, the four vertices of the square ABCD are respectively on the radius OM, Op, and circle O, and the angle POM = 45 ° to find the face of the square ABCD

It is known that the diagonal line of the square is op, and the vertical line of OM passing through point P intersects om at point Q PQ, which is the side length of the square
Because OP = 1 / 2R
So the side length of the square is the root of two times two times one half R
The square has a root of five times two
.
The area is s = 12.5

Draw the largest square in a circle, only tell you that the circle length is 10 meters, calculate the shadow area The shadow area is the area of a circle divided by a square Write the process!! Read divination understand, please answer with numbers.

Very simple, through the center of the square is divided into two right triangle, square side length: 10 / PI, and then square divided by 2, then square root, and then the area of the circle minus the square area. I use my mobile phone, can't give you drawing

For a circle with a radius of 2cm, draw the largest square in the circle, and the rest of the circle is shadow. Calculate the area of shadow part

The diagonal length of the square is the diameter, 4cm
S Square = 4 × (2 × 2 △ 2) = 8 cm ^ (divided into 4 isosceles right triangles with waist length of 2)
S shadow = s circle-s square = 4 π - 8

For a circle with a radius of 1cm, draw the largest square in the circle, and paint the remaining part into shadow to calculate the shadow area

Analysis: the shadow area is equal to the area of the circle minus the square area. The diagonal length of the square in the circle is equal to the diameter of the circle, and the diagonal divides the square into two equal right angle triangles, so the area of the two triangles is equal to the diameter times the radius divided by 2

Draw the largest square in a circle with a diameter of 3cm. Shadow the part outside the square and inside the circle, and calculate the area of the shadow part

3 ÷ 2 = 1.5cm 3x1.5 ÷ 2x2 = 4.5 square centimeter 3.14x1.5x1.5 = 7.065 square centimeter 7.065 - 4.5 = 2.565 square centimeter don't worry, because I am also a student

Given that the side length of the square ABCD is 4, take AB and CD as diameters, draw two semicircles in the square, connect AC and AB, and calculate the shadow area Square, two semicircles, diagonal fork, shadow at the intersection of semicircles and diagonal corners.

The area of the right triangle ABC is 4 * 4 / 2 = 8; the diagonals of the square are perpendicular to each other, so the area of the shadow part is half of the triangle ABC, which is 4 square XX