Root 15 + root 10 - root 5 / root 6 - root 2 + 2 denominator rationalization Is there any simple way to really trouble you

Root 15 + root 10 - root 5 / root 6 - root 2 + 2 denominator rationalization Is there any simple way to really trouble you

The original formula = (√ (5 * 3) + √ (5 * 2) - √ (5 * 1)) / (√ (3 * 2) - √ (2 * 1) + √ (2 * 2))
=√5(√3+√2-1)/[√2(√3-1+√2)]
=√5/√2
=√10/2

(15 times root number 5) / (5 times root number 2 + 2 times root number 5) rationalize denominator

15√5/(5√2+2√5）
=15√5(5√2-2√5)/[(5√2+2√5)(5√2-2√5)]
=(75√10-150)/(50-20)
=(75√10-105)/30
=5/2√10-2

[urgent] in the second grade of mathematics, the following denominators are rationalized. (1) the root of 2 root sign is 6 / 15; (2) 2 root sign 6x / 3 (3) 2 root sign n is the third power 4Mn; (4) root sign a minus B% a 2 minus B 2

(1) The numerator and denominator are multiplied by the root 6 to get: (root 90) / 12 = root 10 / 4
(2) Multiply the numerator and denominator by the root 6x to get the root 6x / 4x
(3) First of all, take 2 to one and open n ^ 3 to get 2m / root n. then multiply the numerator and denominator by the root n to get: (2m times root n) / n
(4) The numerator denominator is multiplied by the root A-B, and then the formula of the square difference of the numerator is expanded to obtain: (a + b) times the root a-b

Denominator rationalization a + 2 times root sign AB + 1 part of B-2 times root sign AB + 1 part of B

Because it is a fraction, so the original formula is equal to ab + B / (1-a-2) times the root sign AB + B, and then under two root signs, AB + B is approximately 1-a-2 fraction a + 2

Let AB be a rational number, and ab satisfies the equation a square + 2B + root sign 2B = 17-4 root sign 2, find the value of a + B

AB is a rational number, and ab satisfies the equation a squared + 2B + radical 2B = 17-4 radical 2
The square of a + 2B = 17
b＝-4
The solution is: a = 5, B = - 4 or a = - 5, B = - 4
So the value of a + B is 5-4 = 1 or - 5-4 = - 9

It is known that a and B are rational numbers and satisfy the equation 5 - √ 3A = 2B + 2 / 3 ×√ 3-A to find the value of AB (√ 3A means: root sign 3 × a) 2 / 3 ×√ 3-A means two-thirds times the root three and then subtract a

5-√3a=2b-2√3/3-a
5+a-2b=√3(a-2/3)
There are rational numbers on the left, so are rational numbers on the right
√ 3 is a rational number only when multiplied by 0
So A-2 / 3 = 0, a = 2 / 3
Right = 0, so the left is equal to 0
So 5 + a-2b = 0
b=(5+a)/2=17/6
a=2/3,b=17/6

If a + B = 0, then a = a = 0 B, a = B C, a + B = 0 d, ab = 0

Cubic root a + cubic root B = 0
Then a and B are the opposite numbers
a+b=0
Select c

It is known that the rational numbers a and B satisfy 5- 3a=2b+2 Three 3-A, find the value of a, B

The original equation can be reduced to (a-2b + 5) + - A-2
3）
3=0，
∵ A and B are rational numbers,
ν 5 + a-2b = 0, and - A-2
3=0．
The solution is - 2 A
3，b=13
6．

Rational denominator: 3-2 root sign 3 / 3 + 2 root sign 3

Multiply the numerator and denominator by 3-2 and radical 3 at the same time

Rational denominator: root 5 / root 3 + 2

=Root 5 * (root 3-2) / ((root 3 + 2) (root 3-2)) = 2 root 5-root 15