It is known that Tana and tanb are the two roots of the equation x + 6x + 7 = 0, then the value of 6tan (a-b) is__ . A. 2 radical 2 b. - 2 radical 2 C. plus or minus 2 radical 2 d. none of the above answers is correct

It is known that Tana and tanb are the two roots of the equation x + 6x + 7 = 0, then the value of 6tan (a-b) is__ . A. 2 radical 2 b. - 2 radical 2 C. plus or minus 2 radical 2 d. none of the above answers is correct

Because Tana and tanb are the two roots of the equation x + 6x + 7 = 0
So Tana + tanb = - 6 Tana * tanb = 7
tana ,tanb
The value of cot (a-b) is
C. Plus or minus 2 root sign
Tana and tanb are the two roots of the equation x + 6x + 7 = 0
According to Weida's theorem
tana+tanb=-6
tanatanb=7
(tana-tanb)^2
=(tana+tanb)^2-4tanatanb
=(-6)^2-4*7
=36-28
=8
Tana ta
The value of cot (a-b) is
C. Plus or minus 2 root sign
Tana and tanb are the two roots of the equation x + 6x + 7 = 0
According to Weida's theorem
tana+tanb=-6
tanatanb=7
(tana-tanb)^2
=(tana+tanb)^2-4tanatanb
=(-6)^2-4*7
=36-28
=8
tana-tanb=±2√2
cot(a-b)
=(1+tanatanb)/(tana-tanb)
=(1+7)/(±2√2)
=±8/(2√2)
=± 2 √ 2
It is known that Tana and tanb are the two roots of the equation x square + 6x + 7 = 0. Then, what is the value of 6tan (a-b)?
Tana and tanb are the two roots of the equation x + 6x + 7 = 0
According to Weida's theorem
tana+tanb=-6
tanatanb=7
(tana-tanb)^2
=(tana+tanb)^2-4tanatanb
=(-6)^2-4*7
=36-28
=8
tana-tanb=±2√2
6tan（a-b）
=6(tana-tanb)/(1+tanatanb)
=6(tana-tanb)/(1+tanatanb)
=6*±2√2/(1+7)
=±12√2/8
=±3√2/2
If the ratio of all items of the integer sequence a (q) is equal to 5, then a (q) is equal to 5?
If A5 = 6, (A5) &# 178; = (A3) × (AM), then:
am=36/(a3)=36/(6－2d)=18/(3－d)
Because: am = A5 + (m-5) d
Then: 6 + (m-5) d = 18 / (3-D)
m－5=6/(3－d)
Because each item of the sequence {an} is an integer, then D, m ∈ Z, that is, the value of 6 / (3-D) may be: ± 6, ± 3, ± 2, ± 1. In addition, considering m > 5 and D ≠ 0, then the value of m-5 may be: 1, 3, 6, then M = 6, 8, 11
If A3, A5, am (M > 5) are equal ratio sequences with common ratio Q (Q > 0), then,
a3=a1+2d
a5=a1+4d=6
am=a1+(m-1)d
a5*a5=(a1+2d)(a1+(m-1)d)
a5=a1+4d=6
M=8
a5=a1+4d=6
a3=a1+2d=6-2d
a5=6
am=a1+(m-1)d=6+(m-5)d
If A3, A5, am (M > 5) are equal ratio sequences with common ratio Q (Q > 0), then,
be
6=q(6-2d),
6+(m-5)d=6q
q=3/(3-d)=1+(m-5)d/6
18=6(3-d)+(m-5)d(3-d)
6D = d... expansion
a5=a1+4d=6
a3=a1+2d=6-2d
a5=6
am=a1+(m-1)d=6+(m-5)d
If A3, A5, am (M > 5) are equal ratio sequences with common ratio Q (Q > 0), then,
be
6=q(6-2d),
6+(m-5)d=6q
q=3/(3-d)=1+(m-5)d/6
18=6(3-d)+(m-5)d(3-d)
6d=d(3-d)(m-5)
The tolerance D ≠ 0,
∴(m-5)(3-d)=6
6=q(6-2d),,q>0
6-2d>0
D5,
m=6,d=-3
M = 7, d = 0.
m=8,d=1
m=11,d=2
M = 6 or 8 or 11
What do you mean by that?
Reduce 1.8:6 / 7 to the simplest integer ratio (). The ratio is (). To calculate the formula
1.8：6/7=9/5：6/7=21：10=2.1
1. 7:56:6 (1 * 7:8 * 7: (6 / 7) * 7 = 7:56:6)
Can we get the exact result of dividing 56 by 6
If the ratio of the sum of the number sequences is not equal to 5, and the sum of the number sequences is not equal to 5
Let an = a1 + (n-1) d, BN = b1d ^ (n-1) = a1d ^ (n-1) A3 = a1 + 2D, B3 = a1d ^ 2a5 = a1 + 4D, B5 = a1d ^ 4A1 + 2D = 5a1d ^ 2A1 + 4D = 5a1d ^ 4D ^ 2 = 1 + (2 / 5) √ 5D = √ [1 + (2 / 5) √ 5] A1 = 2D / (5d ^ 2-1) = 2 √ [1 + (2 / 5) √ 5] / {5 [1 + (2 / 5) √ 5] - 1} = 2 √ [5 + 2 √ 5] / [10 + 4 √ 5] = 1 /
4: 9 / 4 into the simplest integer ratio (), the ratio is () to the formula!
4÷9/4=16/9
4: The ratio of 9 / 4 to the simplest integer (16:9) is (1:7 / 9)
Simplest integer ratio 4: (9 / 4) = (4 * 4): [(9 / 4) * 4] = 16:9
The ratio is: 4 / (9 / 4) = 16 / 9
4: Nine quarters
=(4 * 4): (9 / 4 * 4)
=16：9
It is known that Sn makes the sum of the first n terms of the equal ratio sequence {an}, S4, S10 and S7 equal difference sequence. It is proved that A3, a7 and A6 equal difference sequence
Prove that (1) q = 1, Sn = Na1, then S4, S10, S7 are not arithmetic sequence, so Q ≠ 1 (2) Q ≠ 1sn = A1 (1-Q ^ n) / (1-Q) S4 = A1 (1-Q ^ 4) / (1-Q) S10 = A1 (1-Q ^ 10) / (1-Q) S7 = A1 (1-Q ^ 7) / (1-Q) S4, S10, S7 are arithmetic sequence 2s10 = S4 + S72 (1-Q ^ 10) = (1-Q ^ 4) +
The simplest integer ratio is 0.8 out of 1.8
Turn 0.8 out of 1.8 into the simplest integer ratio (4:9)
0.8/1.8=8/18=4/9=4：9
0.8 out of 1.8
=4 out of 9
=4：9
0.8：1.8
=8：18
=4：9
The ratio of 1.8 and 0.8 is increased to 18 and 8 at the same time, and reduced to 9:4
The first 10 terms of {an} and the value of S10 can be obtained from the known arithmetic sequence {an} where a1 A3 A9 is proportional sequence A2 = 4
a3=a1+2d
a9=a1+8d
It can be seen from the meaning of the title: A3 & # 178; = a1a9
Then (a1 + 2D) & # = A1 (a1 + 8D)
Solution
a1=d
a2=a1+d=2d=4
a1=d=2
be
an=a1+(n-1)d=2+2(n-1)=2n n>0
S10=(a1+a10)*10/2=5(2+20)=110
① It is known that AB is the integer part and the decimal part of radical 36-radical 3 respectively, then the value of a-2b is ()? ② known X & # 178; - 3x + 1
① It is known that AB is the integer part and the decimal part of radical 36-3 respectively, then the value of a-2b is ()?
② Given X & # 178; - 3x + 1 = 0, find the value of √ X & # 178; + 1 / x + 2?
③ Given x = (√ 3) - 1 / (√ 3) + 1, y = (√ 3) + 1 / (√ 3) - 1, how to find the fourth power of X + the fourth power of Y?
Who can do these maths? I need it urgently
① Root sign 3-6
A=4
B = 2-radical 3
A-2b = 2 radical 3
②x²-3x+1＝0
x1+x2=3>0
x1x2=1>0
x1,x2>0
x+1/x=3
√x²+1／x+2
=x+1/x+2
=5
③xy=1
The root sign (√ = 3) + - 3
Y = 2 + radical 3
x^4+y^4
=(x^2+y^2)^2-2x^2y^2
=(7+7)^2-2
=194
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