Find the value of sin 40 ° (Tan 10 ° - root 3)

Find the value of sin 40 ° (Tan 10 ° - root 3)

The original formula is sin40 (sin10 / cos10-sin60 / cos60) = sin40 (sin10cos60-cos10sin60) / cos10cos60 = sin40sin (10-60) / cos10cos60 = - sin40sin50 / (1 / 2 * cos10) = - sin40cos40 / (1 / 2 * cos10) = - 1 / 2 * sin80 / (1 / 2 * cos10) = - 1 / 2 * cos10 / (1 / 2 * c)
(Tan 10 ° - radical 3) × sin 40 °
=(sin10 degrees / cos10 degrees - sin60 degrees / cos60 degrees) * sin40 degrees
=(sin10 degrees, cos60 degrees - sin60 degrees, cos10 degrees) * sin40 degrees / (cos10 degrees, cos60 degrees)
=-Cos40 degrees * sin40 degrees / (cos10 degrees, cos60 degrees)
=-Sin80 degree / (2cos10 degree cos60 degree)
=-1 / (60 degrees)
=-1
The value of (Tan 10 ° - √ 3) sin 40 ° is
(tan10°—√3)sin40°=(tan10°-tan60°)sin40°=(sin10°/cos10° - sin60°/cos60°) sin40°=(sin10°cos60°-cos10°sin60°)sin40°/(cos10°cos60°)=-sin50°sin40°/(cos10°cos60°)=-2cos40°sin40°/(2c...
sin40°（tan10°-√3)=?
tan10-√3
=sin10/cos10-√3
=(sin10-√3cos10)/cos10
=2sin(10-60)/cos10
=-2sin50/cos10
sin40(tan10-√3）
=-(2sin40sin50)/cos10
=-[cos(50-40)-cos(50+40)]/cos10
=-cos10/cos10
=-1
1. The number of subsets of set {0,1,2,3} is ()?
1. The number of subsets of set {0,1,2,3} is ()
A14
B15
C16
D18
What are these subsets?
1. The number of subsets of set {0,1,2,3} is ()
C16
Φ,{0},{1},{2},{3},{0,1},{0,2},{0,3},{1,2},{1,3},{2,3},{0,1,2},{0,1,3},{1,2,3},{1,2,3,4}
Cc 16
Note that both the empty set and the complete set are subsets of it
＝1+4+6+4+1
＝16
16
empty set
0，1，2，3
01，02，03，12，13，23
012，013，023，123
0123
16 in total
Choose C
{0,1,2,3}, {0}, {1}, {2}, {3}, {0,1}, {0,2}, {0,3}, {1,2}, {1,3}, {2,3}, {0,1,2}, {0,1,3}, {1,2,3}, empty sets
15 in total
C16
{0} {1} {2} {3}
{0、1}{0、2}{0、3}{1、2}{1、3}{2、3}
{1、2、3}{0、2、3}{0、1、3}{0、1、2}
Empty sets {0,1,2,3}
Two is to the fourth power
13 out of 24 is a fraction plus a fraction plus a fraction
4,6,8
What is the number of all subsets of set {1,2,3,4}?
What subsets are there,
The fourth power of 2 = 16
empty set
｛1｝,｛2｝,｛3｝,｛4｝
｛1,2｝,｛1,3｝,｛1,4｝,{2,3},{2,4},{3,4}
｛1,2,3｝,｛2,3,4｝｛1,2,4｝｛1,3,4｝
｛1,2,3,4｝
{1} The {2} {3} {4} {1,2} {1,3} {1,4} {2,3} {2,4} {3,4} {1,2,3} {1,2,4} {1,2,3,4} empty set
2^4=16
2 ^ 4 = 16, which is the formula 2 ^ n used to find the number of subsets
One thirteenth is equal to a fraction plus a fraction
1/13=1/26+1/26
1/13=1/26+1/26
1/26+1/26
One in 14 and one in 182 (13 times 14)
One in 13 is equal to one in 14 plus one in (13 × 14)
This kind of question can be answered as follows:
One in n equals one in (n + 1) plus one in [n × (n + 1)]
Hope to help you
If you have any questions, you can ask.
Thank you for your adoption
It's simple. Just give a number and subtract it
You can do it by hand!
On the number of subsets of a set!
If a set has n elements, then its subset will have n of 2
Why is this? How is it pushed out?
Each element has two cases: in a subset; not in a subset, there are n elements, so the subset is 2 * 2 * 2... N 2, that is 2 ^ n
One thirteenth is a fraction plus a fraction
Two different
One thirty nine plus two thirty nine
What is the number of all subsets of an empty set
One is the empty set itself
1