If the image of power function y = f (x) is over 9, then the value of F (25) is?

If the image of power function y = f (x) is over 9, then the value of F (25) is?

If we know that the image of power function y = f (x) passes through a point (9,1 / 3), then f (25) =?
Because it's a power function, let y = x to the power of a {that's the little a above your head. I won't forgive you
Substituting (9,1 / 3), then 1 / 3 = a power of 9
The solution is a = - 1 / 2
So y = x to the - 1 / 2 power
Substituting x = 25, then y = 1 / 5, that is, f (x) = 1 / 5
The answer is over
1. (1 / 2) negative cubic x Sin & # 178; 30 ° minus (radical (- cos 30 °), # 178;) minus 2tan 60 ° / radical 3=
2. In △ ABC, the absolute value 2Sin & # 178; the absolute value of A-1 + (radical 3) (Tanc radical 3) &# 178; = 0, the degree of ∠ B is obtained
1.8 * (1 / 4) *
2. Absolute value square = 0, absolute value = 0 and square = 0
So a = 45 degrees
C = 60 degrees
So angle B = 75 degrees
(I typed it all word by word. I don't know how to ask again.)
The quadratic function f (x) = x2 + QX + R satisfies 1m + 2 + QM + 1 + RM = 0, where m > 0. (1) judge the positive and negative of F (mm + 1); (2) prove that the equation f (x) = 0 has a constant solution in the interval (0,1)
(1) ∵ quadratic function f (x) = x2 + QX + R satisfies 1m + 2 + QM + 1 + RM = 0, where m ＞ 0. F (mm + 1) = m (m (M + 1) 2 + QM + 1 + RM) = − m (M + 1) 2 (m + 2) ＜ 0; (2) when f (0) = R ＞ 0, f (mm + 1) ＜ 0, f (x) is continuous on [0, mm + 1], f (x) has a solution on (0, mm + 1)
First simplify and then evaluate (2x + y) (2x-y) + (X-Y) ^ 2 - (x-2y) ^ 2, where x = 2, y = 1 / 2
(2x+y)(2x-y)+(x-y)^2-(x-2y)^2
=4x²-y²+x²+y²-2xy-(x²+4y²-4xy)
=5x²-2xy-x²-4y²+4xy
=4x²-4y²+2xy
=16-1+2
=17
Find the answers to two questions about acute angle trigonometric function
(1) Given C = 8 times root sign 3, angle a = 60 degrees, find angle B, a, B
(2) Given a = 6, B = 2 times the root sign 3, find the angles a, B, C
It can be proved that both problems are wrong
I can't find it at all
If f (2-x) = f (2 + x), find the value of M
F (2-x) = f (2 + x), indicating that x = 2 is the axis of symmetry of the function
According to f (x) = x & # 178; + (m-1) x + 1, the symmetry axis of the function is x = - (m-1) / 2
Then - (m-1) / 2 = 2
The solution is: M = - 3
f（2－x）＝f（2＋x）
It shows that the axis of symmetry is x = 2
So x = - (m-1) = 2
m=-1
What is the negative second power of 1?
I'll give you an answer. Just a moment
Acute angle trigonometric function in Junior Three
In △ ABC, angle a = 120 °, ab = 5, BC = 7, find the length of AC. (alphabetic order: bottom left is B, bottom right is C, vertex is a.)
Extend Ca and make a vertical line through B to intersect CA extension line at D because the angle BAC = 120 ° so the angle bad = 60 ° because AB = 5 so ad = 5 / 2 BD = 5 √ 3 / 2 because BD is perpendicular to CD so the angle d = 90 ° so in triangle BDC, BC ^ 2 = BD ^ 2 + CD ^ 2, namely 7 ^ 2 = (5 √ 3 / 2) ^ 2 + CD ^ 2 so CD = 11 / 2 so AC = cd-ad = 11 / 2-5 / 2
Let f (x) be continuous on [0,1], and f (0) = f (1). It is proved that there must be x belonging to [0,1 / 2], such that f (x) = f (x + 1 / 2)
Let f (x) = f (x) - f (x + 1 / 2)
If f (0) = f (1) - f (1 / 2)
F(1/2)=f(1/2)-f(0)=f(1/2)-f(1)=-F(0)
So f (0) is different from F (1 / 2)
So there must be t ∈ [0,1 / 2] such that f (T) = f (T) - f (T + 1 / 2) = 0
So the original proposition is proved