If A. B is a rational number and satisfies | A-2 | + (B + 3) (B + 3) = 0, find the a power of B

If A. B is a rational number and satisfies | A-2 | + (B + 3) (B + 3) = 0, find the a power of B

According to the proposal: A-2 = 0, B + 3 = 0, so a = 2, B = - 3, so the a power of B is - 3, so the second power is 9
Because | A-2 | ≥ 0, | B + 3 | ≥ 0
And | A-2 | + | B + 3 | = 0
So | A-2 | = 0 and | B + 3 | = 0
a-2=0,b+3=0
The solution is a = 2, B = - 3
b^a=(-3)^2=9
Let f (x) be a function defined on R, and for any real number x and y, F: (x + y) = f (x) + F (y). (1) prove that f (x) is an odd function; (2) if f (- 3) = a, use a to express f (12); (3) if f (x) > 0 when x > 0, then f (x) is an increasing function on R
(1) Obviously, the domain of definition of F (x) is r, symmetric with respect to the origin. For all x and y, f (x + y) = f (x) + F (y), let x = y = 0, then f (0) = 2F (0), f (0) = 0. Let y = - x, then f (0) = f (x) + F (- x), f (- x) = - f (x), f (x) are odd functions. (2) ∵ f (- 3) = a, f (x) is odd function, ∵ f (3) = - f (- 3) = - A Let f (x + y) = f (x (x + y) = f (x) (f (x + y) = f (x (x + y) = f (x (x + y) = f (x (x) + F (12) = f (12) = f (x (x + y) = f (6 + 6) = f (6) (f (12) = f (x (x + y) = f (6) = f (6 + 6) = f (6) = f (6 (6 + 6) = f (6) = f (6 + 6) = f (6) = f (6) = f (6) = f (6 (6) = f (6 (6) = 6 (6) = 6 (6 (6) = 6 (6 (6 (6) = 6 (6 (6 (6) = 6 (6 (6 (6 (6 (6) = 6 (6 (6 (6 (6 (6 (6 (6) = 6 (6 (6 (6 (6 (6 (6) = f (6 (6) = f (6 (6 (6 (6) (f (6 (6 (6 (6 (6 (6 (6(x) If f (x 2) - f (x 1) > 0, f (x 2) > F (x 1) ‖ f (x 1) is an increasing function on R
When x > 0, f (x) > 1, and for any x, y always has f (x + y) = f (x) × f (y)
Let x = 2, y = 0f (2) = f (0) f (2) f (2) ≠ 0f (0) = 1, if x0f (x) f (- x) = f (0) = 1F (- x) > 0, f (0) > 0, so any x ∈ R, f (x) > 0, take x1, X2, X1 > x2 in R, let x + y = x1, x = X2, then y = x1-x2f (x1) = f (x2) * f (x1-x2) f (x1) / F (x2) = f (x1-x2)
Hello, what question do you want to answer? Questions: (1) prove that when x is less than 0, f (x) is greater than 0 and less than 1. (2) prove that f (x) is an increasing function on R. (3) if f (x square) * f (2x-x square + 2) is greater than 1, find the value range of X
An acute angle trigonometric function in the third grade of junior high school
It is known that in RT △ ABC, ∠ B = 30 degree and ∠ C = 90 degree. On the basis of this triangle, an appropriate auxiliary line is added to find the value of Tan 15 degree
Extend CB to D, make BD = AB, connect ad, then ∠ d = 15 °
Let AC = a, then AB = 2A. According to Pythagorean theorem, the value of BC can be obtained;
And CD = AB + BC, so we can get tan15 ° = AC / CD
It is known that the periodic function f (x) is an odd function defined on R. the period is 2. F (1) + F (2) + F (3) + +f(2011)=?
Because f (x) is an odd function defined on R, f (0) = 0,
We also know that the function f (x) is a periodic function with period 2, so - f (1) = f (- 1) = f (- 1 + 2) = f (1), so f (1) = 0
So for any integer x, f (x) = 0. So f (1) + F (2) + F (3) + +f(2011)=0.
= 0
Draw a picture
Or for example, y = SiNx has a period of 2 π, so for example, y = sin (π x) has a period of 2 and is an odd function
sinπ+sin2 π+sin3 π+.....+sin 2011 π=0
On the definition of odd function f (n) + F (- n) = 0
Definition of periodic function f (- n) = f (- N + 2n) = f (n)
From the above two expressions, we can get f (n) = 0, where n is an integer.
So f (1) + F (2) + F (3) + +f(2011)=0
To the power of positive integer exponent: 3A to the power of - 2, 2 / C to the power of - 1, m to the power of - 2 =?
=a²/6m²c
Square of 1 / 9A square of 2 / C 1 / M
Your Chinese level is too high, or my Chinese level is too low!
As shown in the figure, in order to measure the height of the mountain AC, the elevation angle of the top a is 30 ° measured at the horizontal plane B, from B along the BC direction forward 1000m, to D, and the elevation angle of the top a is 45 ° measured, then the height of the mountain is___ .
In RT △ ABC, from tanb = ACBC, BC = actan30 ° is obtained. ① in RT △ ACD, from Tan ∠ ADC = ACDC, CD = actan45 ° is obtained. ② from ① - ②, AC = bd1tan30 ° - 1tan45 ° is 500 (3 + 1) M. that is to say, the mountain height is 500 (3 + 1) M
Let f (x) be an odd function with a period of 3 and f (- 1) = - 1, then f (2008)=______ .
Because the period of the function is 3, so f (2008) = f (2007 + 1) = f (1) and because the function is odd, and f (- 1) = - 1, so f (1) = - f (- 1) = 1, so f (2008) = 1, so the answer is: 1
To make the polynomial MX ^ 3 + 3nxy ^ 2 + 2x ^ 3-xy ^ 2 + y contain no cubic term, find the value of 2m + 3N
mx^3+2x^3=0
m=-2
3nxy^2-xy^2=0
n=1/3
2m+3n=-4+1=-3