F (x) = 1-2x / (x ^ 2 + X + 1), find the derivative of F (x)

F (x) = 1-2x / (x ^ 2 + X + 1), find the derivative of F (x)

f'(x)=0- [ 2(x^2+x+1)-2x(2x+1)]/(x^2+x+1)^2
=2(x^2-1)/(x^2+x+1)^2
How to find the derivative of F (x) = x ＾ 3 + ax ＾ 2 + X + 1? F ′ (x) = 3x ＆ 178; + 2aX + 1 [with formula: (x ＆ 8319;) ′ = NX ＆ 8319; & 8315; & 185; a as constant jmru]
Derivative of F (x) = x-2x ^ 1 / 2
f'(x)=1-x^(-1/2)=1-1/√x
If a △ B = C (a, B, C are all natural numbers, and B ≠ 0), then the greatest common divisor of a and B is______ The least common multiple is______ .
It is known that a △ B = C (a, B, C are all natural numbers, and B ≠ 0), indicating that a is a multiple of B, then the greatest common divisor of a and B is B, and the least common multiple is a;
The derivative of y = Xe ^ x,
Y = Xe ^ x, then:
y'=(x)'(e^x)＋(x)(e^x)'
.=e^x＋xe^x
.=(x＋1)e^x
Y = e ^ x + Xe ^ x step by step derivation
It is known that the sum of two natural numbers is 54, and the difference between the least common multiple and the greatest common divisor is 114
Let two natural numbers be x and y, then x = AB, y = CB, and it can be seen from the question that a, B, C are all positive integers, then AB + CB = 54 = B (a + C) = 2 × 3 × 9, abc-b = 114 = B (ac-1) = 2 × 3 × 19, because a, B, C are all positive integers, so B may be 2 or 3 or 6. After the test, B is 2 or 3, a, C has no positive integer solution. So B can only be 6, so a = 4, C = 5. So x = AB = 24 & nbsp; & nbsp; Y = CB = 30. A: the two numbers are 24 and 30 respectively
Find y = √ x + Xe Λ x derivative
y'=0.5/√x+(e^x+xe^x)
Use the formula (UV) '= u'v + UV'
(e^x)'=e^x
Two numbers are prime to each other, and their least common multiple is 153
153=3*3*17
3 and 17 are prime numbers. Therefore, the required two numbers cannot be 3 and 3 * 17 = 51, because then they are not coprime numbers, and the least common multiple is 51 or 153,
So the answer is 3 * 3 = 9 and 17
153/3=51
51/3=17
So the two numbers are 9 and 17
The least common multiple of two coprime numbers is their product
153=3^2*17
Two numbers are prime, so 3 ^ 2 is in the same number, so these two numbers are 9 and 17
153=3*3*17，
Since two numbers are coprime, they cannot have the same prime factor. Therefore, if there is 3 in the two numbers, they cannot give the other 3 to another number. Otherwise, there is a common factor 3, so the other number can only be 17, which is 3 * 3 = 9.
They are 9 and 17.
It is known that the sum of two natural numbers is 54, and the difference between the least common multiple and the greatest common divisor is 114
Let two natural numbers be x and y, then x = AB, y = CB, and a, B, C are all positive integers, then AB + CB = 54 = B (a + C) = 2 × 3 × 9, abc-b = 114 = B (ac-1) = 2 × 3 × 19, because a, B, C are all positive integers, so B may be 2 or 3 or 6
Finding the (- X & # 178;) derivative of y = Xe
y=xe^(-x^2)
y'=x'e^(-x^2)+x[e^(-x^2)]'
=e^(-x^2)+xe^(-x^2)*(-x^2)'
=e^(-x^2)+xe^(-x^2)*(-2x)
=e^(-x^2)-2x^2*e^(-x^2)
=(1-2x^2)*e^(-x^2)
y'=x' e^(-x^2)+x*e^(-x^2)*(-2x)=(1-2x^2)*e^(-x^2)