The square of X + 3x-8 = the square of 20 / x + 3x solves X

The square of X + 3x-8 = the square of 20 / x + 3x solves X

Let X & sup2; + 3x be y;
Y-8=20/Y;
Y²-8Y-20=0;
(Y-10)(Y+2)=0;
Y = 10 or - 2;
So:
1: X & sup2; + 3x = 10, x = 2 or - 5;
2: X & sup2; + 3x = - 2, x = - 1 or - 2;
There are four solutions
X is equal to plus or minus (4 + 2 (101)). Note: () stands for the root sign
Find the solution set of the following inequalities: (1) 4x ^ 2-4x is greater than 15; (2) 13-4x ^ 2 is greater than 0; (3) x ^ 2-3x-10 is greater than 0; (4) x (9-x) is greater than 0
(1) 4X ^ 2-4x greater than 15
4x^2-4x-15>0
(2x-5)(2x+3)>0
x> 5 / 2 or X
Factorization of square b-2b=
Bsquare-2b = B (b-2)
b(b-2)
b^2-2b=b(b-2)
⒋ ⒊ ⒉
6X +5X -38X +5X-6
6(X^4+1)+5X(X^2+1)-38X^2
=6[(X^2+1)^2-2X^2]+5X(X^2+1)-38X^2
=6(X^2+1)^2+5X(X^2+1)-50X^2
.
=(X-2)(X+3)(3x+1)(2x-1)
6X^4+5X^3-38X^2+5X+6
=(6x^4-15x^3+6x^2)+(20x^3-50x^2+20x)+(6x^2-15x+6)
=3x^2(2x^2-5x+2)+10x(2x^2-5x+2)+3(2x^2-5x+2)
=(3x^2+10x+3)(2x^2-5x+2)
=(3x+1)(x+3)(2x-1)(x-2)
You can figure out which is right
How to calculate the square of (a + b) (a-b) + 2B
Solution: use the adjustment formula,
Original formula = a * A-B * B + 2B * b = a * a + b * B
The original formula = the square of a - the square of B + the square of 2B
=Square of a + square of B
Super high score for several second grade factorization problems
The square of M (Y-X) + the square of n (X-Y)
The square of the second trace (x's Square - 2x) - 1
The cubic power of the third trace 3A (x-1) - the square of 2B (1-x)
Square of the fourth (x + y) - 4 (x + Y-1)
Square of the fifth trace 4 (1 + 2x-3y) + (3y-2x)
The square of the sixth trace (the fourth power of X + 1) - (the square of 2x)
The sixth course may be a little difficult. It doesn't matter if you can't do it. The process doesn't need to be too detailed. You can basically understand it
Of course, detailed I will add points
The first problem is the square of M (Y-X) + the square of n (X-Y) = (Y-X) (m-n) = (M + n) (m-n) (Y-X) the second way is the square of x-2x-1 = (x ^ 2-2x-1) (x ^ 2-2x + 1) = (x ^ 2-2x-1) (x-1) ^ 2 the third way is the square of 3A (x-1) - 2b (1-x) = (3ax-3a-2b) (x-1) the fourth way is
1.(n+m)(n-m)(x-y)
2.=x^4-4x^3+4x^2-1
=(x^4-1)-(4x^3-4x^2)
=(x^2+1)(x+1)(x-1)-4x^2(x-1)
=(x^3-3x^2+x+1)(x-1)
3. (3ax-3a-2b) (x-1) ^ 2 (note that this is squared)
4.=x^2-4x+y^2-4y+2xy+4
=(x+y+2)^2
5.（2x-3y+2)^2
6.（x2+1）^2*（x+1）^2*（x-1）^2
M (Y-X) - n (Y-X) = (Y-X) (m-n) = (M + n) (m-n) (Y-X)
1.=(m^2-n^2)(y-x)=(m+n)(m-n)(y-x)
2.=(x^2-2x+1)(x^2-2x-1)=(x-1)^2(x-1-√2)(x-1+√2)
3.=(x-1)^2*{3a(x-1)-2b}=(x-1)^2*(3ax-3a-2b)
4.=(x+y)^2-4(x+y)+4=(x+y-2)^2
5.=4+4(2x-3y)+(2x-3y)^2=(2x-3y+2)^2
6.=(x^4+1)^2-4x^4=x^8+2x^4+1-4x^4=x^8-2x^4+1=(x^4-1)^2
={(x^2+1)(x^2-1)}^2
={(x^2+1)(x+1)(x-1)}^2
One
=m^2（y-x)-n^2(y-x)=(y-x)（m^2-n^2)=(m+n)(m-n)(y-x)
Two
=(x^2-2x+1)(x^2-2x-1)=(x+1)(x-1)(x-1-/2)(x-1+/2)
Three
=(x-1)^2(3ax-3a-2b)
Four
=(x+y)^2-4(x+y)+4=(x+y-2)^2
Five
=(3y-2x)^2-4(3y-2x)+4=(3y-2x-2)^2
Six
=(x^4-2x^2+1)(x^4+2x^2+1)=(x^2-1)^2(x^2+1)^2=(x+1)^2(x-1)^2(x^2+1)^2
Calculate the square of (A's Square) + (A's square + 2B's Square)
=The fourth power of a + the fourth power of a + the fourth power of 4A & # 178; B & # 178; + the fourth power of 4B
=The fourth power of 2A + 4A & # 178; B & # 178; + 4B
Second grade factorization problem. Urgent. Quick. Add 10 points
1（x+1）（x+2）（x+3）（x+4）-24
2 a squared - B squared - 2bc-c squared
The third power of 3 (X-Y) + 4y-4x
It is known that a + B = 3 / 2, ab = 1?
The absolute value of the square of 5 (negative root 3) - 2 root 18 + (root 2-1) to the power of 2011 (1 + root 2) to the power of 2010 + 1-root 2
The square of 6 3x (a + 2b) - 6xy (a + 2b)=
7. Power n of - 12x + power n plus 1 of 4x + power N-1 of 32x
Square of 8 (m-n) - 4 (m-n-1)
The square of 9 x - 5x + 6
10 x squared-26x-56
11 x squared + 5xy + 6y squared
Please write down the process
Given the square of root x + Y-3 + X - 4xy + 4Y = 0. Find the value of 3x + 2Y
It is known that a and B are rational numbers. Try to explain that the square of a + the square of B - 6A + 4B + 19 is positive
^What do you mean?
1, (x + 1) (x + 2) (x + 3) (x + 4) - 24 = (x ^ 2 + 5x + 4) (x ^ 2 + 5x + 6) - 24 = (x ^ 2 + 5x) ^ 2 + 10 (x ^ 2 + 5x) + 24-24 = (x ^ 2 + 5x) (x ^ 2 + 5x + 10) = x (x + 5) (x ^ 2 + 5x + 10) 2, the square of A-B, the square of B-C = a ^ 2 - (B + C) ^ 2 = (a + B + C) (a-b-c) 3, the third power of X-Y + 4Y -
Question 2 A & sup2; - (B + C) & sup2; question 3 (X-Y) & sup2; - 4 question 4-13 / 3
(4a cubic / 3B Square) square * (- 3B / 2A Square) cubic * (- B / 3A Square)
Just remember (a ^ b) ^ C = a ^ (BC)
(4a^3/3b^2)^2*(-3b/2a^2)^3*(-b/3a)^2
=[16a^6/(9b^4)]*[-27b^3/(8a^6)]*[b^2/(9a^2)
=-2b/3a^2
Factorization
(1) The third power of X + the square of 3x-4x-12=
(2) If the square + 7x + a of the polynomial 5x has a factor (x + 1), then the polynomial can be decomposed into
(3) Square of a square of b-square of A-Square of B + 1=
(4) (square of 1-x) (square of 1-y) - 4xy=
(5) The square of (A-1) (a-2b-1) + B=
(6) The square of X - the square of Y - 6x + 9=
(7) 4X + 1 / 4-2x-9y=
(1) The cubic power of X + the square of 3x-4x-12 = x & sup2; (x + 3) - 4 (x + 3) = (X & sup2; - 4) (x + 3) = (x + 2) (X-2) (x + 3) (2) if the square of the polynomial 5x + 7x + A has a factor (x + 1), then the polynomial can be decomposed into the square of (x + 1) (5x + 12) (3) a, the square of the square of B-A, and the square of B + 1 = A & sup2; (B &...)
x^3+3x^2-4x-12
=x^3-4x+3x^2-12
=x(x^2-4)+3(x^2-4)
=(x^2-4)(x+3)
=(x+2)(x-2)(x+3)
5x^2+7x+a
=(x+1)(5x+a)
a^2b^2-a^2-b^2+1
=a^2(b^2-1)-(b^2-1)
=(a^2-1)(b^2-1)
=(a) unfold
x^3+3x^2-4x-12
=x^3-4x+3x^2-12
=x(x^2-4)+3(x^2-4)
=(x^2-4)(x+3)
=(x+2)(x-2)(x+3)
5x^2+7x+a
=(x+1)(5x+a)
a^2b^2-a^2-b^2+1
=a^2(b^2-1)-(b^2-1)
=(a^2-1)(b^2-1)
=(a-1)(a+1)(b-1)(b+1)
(1-x^2)(1-y^2)-4xy
=x^2y^2-x^2-y^2+1-4xy
=x^2y^2-2xy+1-x^2-y^2-2xy
=(xy-1)^2-(x+y)^2
=(xy-1+x+y)(xy-1-x-y)
(a-1)(a-2b-1)+b^2
=(a-1)[(a-1)-2b]+b^2
=(a-1)^2-2b(a-1)+b^2
=(a-1-b)^2
x^2-y^2-6x+9
=x^2-6x+9-y^2
=(x-3)^2-y^2
=(x-3-y)(x-3+y)
4x^2+1/4-2x-9y^2
=4x^2-2x+1/4-9y^2
=(2x-1/2)^2-9y^2
=(2x-1 / 2 + 3Y) (2x-1 / 2-3y) Stow
(1) (x-2)*(x+2)*(x+3)
(2) (x+1)*(5x+2)
(3) (b-1)*(b+1)*(a-1)*(a+1)
(4) (x*y+y-1+x)*(-y+x*y-x-1)
(5) (a-b-1)^2
(6) (x-3+y)*(x-3-y)
(7) 1/4*(4*x-1+6*y)*(4*x-1-6*y)
(x+3)(x+2)(x-2)
5(x+1)(x+2/5)
(a+1)(a-1)(b+1)(b-1)
(xy+x+y-1)(xy-x-y-1)
(a-b-1)^2
(x+y-3)(x-y-3)
(2x+3y+1/2)(2x-3y+1/2)