Find the solution set of the following inequality: 1.4x & sup2; - 4x ＞ 152.13 × 4x & sup2; > 0.3.x & sup2; - 3x-10 ＞ 0.4.x (9-x) ＞ 0

Find the solution set of the following inequality: 1.4x & sup2; - 4x ＞ 152.13 × 4x & sup2; > 0.3.x & sup2; - 3x-10 ＞ 0.4.x (9-x) ＞ 0

(2x-5)(2x+3)>0
x>5/2 x0
X is not equal to 0
(x-5)(x+2)>0
x>5 x
If a = {x │ x-3x + 2 = 0} B = {x │ 0 ＜ x ＜ 5, X ∈ n} satisfies the condition that a is included in C, and the number of sets C that are really included in B is?
A = {x | x = 1 or 2}, B = {x | x = 1,2,3,4} satisfies that a is contained in C, and C is really contained in B set. There are three C = {x | x = 1,2} C = {x | x = 1,2,3} C = {x | x = 1,2,4}
If | A-2 | + | B-3 | + | C-4 | = 0, find the value of 2A + 3B + 4C
∵|a-2|+|b-3|+|c-4|=0
∴a-2=0
b-3=0
c-4=0
∴a=2,b=3,c=4
∴2a+3b+4c
=4+9+16
=29
Because the absolute value is greater than or equal to 0, so a = 2, B = 3, C = 4, so 2A + 3B + 4C = 29
Wait! Factorization
(2-3y) (9y ^ 2 + 6y + 4) and (x + 2) ^ 3 - (X-2) ^ 3 and 1 / 2 x ^ 4-8 and x ^ 4 + 7x ^ 2-8
There are also a ^ 4-A ^ 3 plus a ^ 2-A and 4A ^ 2-9b ^ 2 plus C ^ 2-4ac and (AX plus by) ^ 2 plus (BX ay) ^ 2, I give 20 points fast
(2a-3b+4c)(4c-2a-3b)=
The original formula = [(4c-3b) + 2A] [(4c-3b) - 2A]
=(4c-3b)²-(2a)²
=16c²-24bc+9b²-4a²
=【(4c-3b)+2a】【(4c-3b)-2a】
=(4c-3b)²-4a²
=16c²-24bc+9b²-4a²
(2a-3b+4c)(4c-2a-3b)
=((4c-3b)+2a)((4c-3b)-2a)
=(4c-3b)^2-(2a)^2
=16c^2-24bc+9b^2-4a^2
=-4a^2+9b^2+16c^2-24bc
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（2a-3b+4c)(4c-2a-3b)
=[(4c-3b)+2a][(4c-3b)-2a]
=(4c-3b)^2-4a^2
=16c^2-24bc+9b^2-4a^2
Urgent! Factorization
M ^ 3M ^ 2-m ^ 5 and x ^ 4 plus 6x ^ 2 plus 9 and 4A ^ 3-4A ^ 2 plus a
m^3m^2-m^5
=m^(3X2)-m^5
=m^6-m^5
=m^5(m-1)
X ^ 4 plus 6x ^ 2 plus 9
Namely: x ^ 4 + 6x ^ 2 + 9
=(x^2+3)^2
4A ^ 3-4A ^ 2 plus a
Namely: 4A ^ 3-4A ^ 2 + A
=a(4a^2-4a+1)
=a(2a-1)^2
If 2A = 3B = 4C, then a: B: C=______ .
Let 2A = 3B = 4C = k, a = K2, B = K3, C = K4, a: B: C = K2: K3: K4 = 6:4:3
On factorization
The following deformation from left to right is factorized as ()
A.(3-x)(3+x)=9-x^2 B.m^3-n^3=(m-n)(m^2+mn+n^2)
C.(y+1)(y+3)=―(3-y)(y+1) D.4yz-2y^2z=2y(2z-yz)+z
West West
B
Factorization, which transforms a polynomial into the product of several simplest integers, is also called factorization
A is the calculation
C is another symbol
D is not finished yet
B
B
B. Factorization is to transform a formula with addition and subtraction into the product of several formulas
B
B
Factorization of b-factorization transforms a polynomial into the product of several simplest integers. This transformation is called factorization of the polynomial, also known as factorization.
Factorization (factorization) is to transform a polynomial into the product of several simplest integers. It's obviously B
B
Factorization is to transform a formula with addition and subtraction into the product of several formulas. The other three are not
B
Calculation (2a + 3b-4c) (3b-2a-4c)
(2a+3b-4c)(3b-2a-4c)
Adjust the order of the algebraic expressions in brackets slightly
=(3b-4c+2a)(3b-4c-2a)
See the law
=(3b-4c)^2 - (2a)^2
=9b^2-24bc+14c^2 -4a^2
=[(3b-4c)+2a][(3b-4c)-2a]
=(3b-4c)²-(2a)²
=9b²-24bc+16c²-4a²
5 / A ^ 2-5 and 9x ^ 2-y ^ 2-4y-4 and negative 1 / 3 x ^ 2 plus 3Y ^ 2
a^2/5-5
=1/5(a^2-25)
=1/5(a+5)(a-5)
9x^2-y^2-4y-4
=9x^2-(y+2)^2
=(3x+y+2)(3x-y-2)
-1/3x^2+3y^2
=1/3(9y^2-x^2)
=1/3(3y+x)(3y-x)