If u = R, a = {X / 0}

If u = R, a = {X / 0}

A = {x | 0 ＜ x ＜ 2}, B = {x | x ＞ 1 or X ＜ - 3}
CUA = {x | x ≤ 0 or X ≥ 2}
CuB={x|-3≤x≤1}
Then (CUA) ∩ (cub) = {x | - 3 ≤ x ≤ 0}
If you don't understand, please hi me, I wish you a happy study!
CuA={x|x≤0，x≥2}
CuB={x|-3≤x≤1}
So (CUA) ∩ (cub) = {x | - 3 ≤ x ≤ 0}
Given the set u = {x | x less than or equal to 4} a = {x | - 2 less than x less than or equal to 3} B = {x | x less than or equal to 0} find CUA, cub
CUA = {X / X ≤ - 2 or 3 ≤ x
Given the complete set u = a ∪ B = {x ∈ n | 0 ≤ x ≤ 10}, a ∩ (∁ UB) = {1, 3, 5, 7}, find the set B
U = a ∪ B = {x ∈ n | 0 ≤ x ≤ 10} = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, {1, 3, 5, 7} ⊆ a, but B does not contain {1, 3, 5, 7}, which is represented by Venn graph, as shown in the figure ∪ B = {0, 2, 4, 6, 8, 9, 10}
Definition & nbsp; if a ⁃ B = a + 2b2b, then 3 ⁃ 4 ⁃ 12=______ .
According to the meaning of the question: 3 ⁃ 4 ⁃ 12, = 3 + 2 × 42 × 4 ⁃ 12 = 118 ⁃ 12, = 118 + 2 × 122 × 12, = 118 + 1, = 238; so the answer is: 238
20 examples of factorization
Give some examples, thank you!
Factorization 3a3b2c-6a2b2c2 + 9ab2c3 = 3AB ^ 2 C (a ^ 2-2ac + 3C ^ 2) 3. Factorization XY + 6-2x-3y = (x-3) (Y-2) 4. Factorization X2 (X-Y) + Y2 (Y-X) = (x + y) (X-Y) ^ 2 5. Factorization 2x2 - (a-2b) x-ab = (2x-a) (x + b) 6. Factorization a4-9a2b2 = a ^ 2 (...)
Definition & nbsp; if a ⁃ B = a + 2b2b, then 3 ⁃ 4 ⁃ 12=______ .
According to the meaning of the question: 3 ⁃ 4 ⁃ 12, = 3 + 2 × 42 × 4 ⁃ 12 = 118 ⁃ 12, = 118 + 2 × 122 × 12, = 118 + 1, = 238; so the answer is: 238
An example of factorization
As for the factorization problem of X, the coefficient should not be too large. It does not contain any other letters. It is not suitable for solving. The more questions, the better. Keep improving,
x²+2x+1=（x+1）²
2a-b-ab + BC + 2Ac x-y-2x-4y-3 5A m-15am + 3abm-9bm x to the fourth power + 1 / 4Y to the fourth power 2x-x-5x-2
I want some ready-made questions
Given that a is not equal to B, the square of a + 2a-5 = 0, the square of B + 2b-5 = 0, find the square of a * B + the square of a * B
a^2*b+a*b^2=(a+b)*ab
A ^ 2 + 2a-5 = 0, so (a + 1) ^ 2 = 6
A and B are the two square roots of 6 minus 1
A. B is the two roots of the square of X + 2x-5 = 0. There are a + B = - 2; a * b = - 5
So the result is 10
We can see that a and B are the two roots of the equation x ^ 2 + 2x-5 = 0
A^2B+AB^2=AB(A+B)
A+B=-2/2=-1
AB=-5/1=-5
So a ^ 2B + AB ^ 2 = (- 1) (- 5) = 5
Factorization exercises
One 7x & # 178; - one two X & # 178; + 2 √ 2x + 2 three 16A & # 178; - 5 four (2 √ 5-4) × (2 √ 5 + 4) "√" is (root sign)
Quadratic radical addition and subtraction: one √ 75 ＋ 48 - √ 27 two 4 √ 0.5 ＋ 0.4 √ 50 - √ 0.125 three (48 √ - 3 √ 27) △ 3
Four (2 + 3 √ 6) &;
(√7x-1)(√7x+1)
(x+√2)(x+√2)
(4a-√5)(4a+√5)
(2√5)^2-4^2=20-16=4
(5√3)-(4√3)-(3√3)
4√0.5＋4√0.5－0.5√0.5=7.5√0.5=15/4√2
Three? Is Chao wrong
2^2+（3√6）^2+2*2*3√6
It is known that a is not equal to B and satisfies the square of 2a-2a-1 = 0, the square of 2b-2b-1 = 0; find the square of (A-1) + the square of (B-1)
From the square of 2a-2a-1 = 0 and the square of 2b-2b-1 = 0, we know that a and B are two roots of the quadratic equation 2x ^ 2-2x-1 = 0, so a + B = - (- 2) / 2 = 1, ab = - (1 / 2), so (A-1) ^ 2 + (B-1) ^ 2 = a ^ 2 + B ^ 2-2 (a + b) + 2 = (a + b) ^ 2-2ab-2 (a + b) + 2 = 1-2 * (- 1 / 2) - 2 * 1 + 2 = 2