Given: set a = {x | x square-4x + 3 is greater than or equal to zero}, B = {x | 5-x / x + 2 > 0}, complete set u = R, find: (1) intersection B (2) (CUA) intersection B

Given: set a = {x | x square-4x + 3 is greater than or equal to zero}, B = {x | 5-x / x + 2 > 0}, complete set u = R, find: (1) intersection B (2) (CUA) intersection B

Set a: X Λ 2-4x + 3 "0, get (x-1) (x-3)" 0, get X "3 or X" 1 set B: 5-x / x + 2 > 0, get (X-5) / (x + 2) < 0, get (X-5) (x + 2) < 0, get - 2 < x < 5 (1) a intersection B, draw coordinate axis = {x | 2 < x "1,3 ≤ x < 5} (2, CUA = {x | 1 < x < 3}, so get (CUA) intersection B = {x | 1 < x}
If u = R, a = {X / x + 1 greater than = 1}, B = {X / X square-x-12 less than = 0}, then (CUA) intersection B is equal to
Is C [- 3, - 1] d (- 3, - 1) C
A (-1,4) B[-1,4) C [-3,-1)
A:x>=0
B:-3
Is C [- 3, - 1] d (- 3, - 1) C
A:x>=0
B:-3
Given that the a power of 2 is equal to 5, and the B power of 3 is equal to 7, find the 2A power of 2 plus the 3B power of 3
Original formula = (2 ^ a) ^ 2 + (3 ^ b) ^ 3
=5^2+7^3
=25+21
=46
Factorization!
M (M + n) (m-n) - M (M + n) & sup2;, where M + n = 1, Mn = - 1 / 2
m(m+n)(m-n)-m(m+n)²
=m(m+n)(m-n-m-n)
=-2mn(m+n)
=1
Simplified evaluation: 3a2b-2 [2ab2 - (2ab-a2b) + AB] + 3ab2, where (a-b) 2 + | ab-2 | = 0
∵ (a-b) 2 + | ab-2 | = 0, ∵ A-B = 0, ab-2 = 0, that is, A-B = 0, ab = 2, then the original formula = 3a2b-4ab2 + 4ab-2a2b-2ab + 3ab2 = a2b-ab2 + 2Ab = AB (a-b) + 2Ab = 4
1. Factorization: a square + b square + 4A + 2B + 3=________
2. Factorization factor: 9x square - 6x-y square + 4y-3_______
3. Factorization factor: the square of X + 5xy + X + 3Y + 6y________
4. Factorization factor: the square of AB (a + b) - (a + b) + 1__________
5. Factorization factor: the square of X - the square of 2x-2y + 4Y XY___________
6. Decomposition factor: (X-2) cube - (Y-2) cube - (X-Y) cube=___________
7. Decompose the factor in the range of real number: the fourth power of X + the cube of X - the square of 3x - 4x-a=________________
8. Factorization: X (x-1) + y (y + 1) - 2XY=__
9. Factorization: cube of X + square of 5x + 3x-9
1. Factorization
2. Factorization factor: 9x square - 6x-y square + 4y-3_
=(3x-1)^2-(y-2)^2
=(3x+y-3)(3x-y+1）______
3. Factorization factor: the square of X + 5xy + X + 3Y + 6y
=(x+2y)(x+3y)+(x+3y)
=(x+3y)(x+2y+1)________________
5. Factorization factor: the square of X - the square of 2x-2y + 4Y XY
=(x+y)(x-2y)-2(x+y)
=(x+y)(x-2y-2)___________
6. Decomposition factor: (X-2) cube - (Y-2) cube - (X-Y) cube
=(x-2-y+2)[(x-2)^2+(x-2)(y-2)+(y-2)^2]-(x-y)^3
=(x-y)[(x-2)^2+(x-2)(y-2)-(x-y)^2]
=(x-y)[(2x-2-y)(y-2)+(x-2)(y-2)]
=(x-y)(y-2)[(2x-2-y+x-2)]
=(x-y)(y-2)(3x-y-4)________
8. Factorization: X (x-1) + y (y + 1) - 2XY
=x^2-x+y^2+y-2xy
=(x-y)^2-(x-y)
=(x-y)(x-y-1)
Is this the first day of junior high school???
2. Decomposition factor: 9x square - 6x-y square + 4y-3 = (3x + Y-3) (3x-y + 1)
1. a^2-b^2+4a+2b+3 9.x^3+5x^2+3x-9
=(a^2+4a+4)-(b^2-2b+1) =x^2(x+3)+2x^2+3x-9
=(a+2)^2-(b-1)^2 =x^2(x+3)+(2x-3)(x+3)
=[(a + 2
1. a^2-b^2+4a+2b+3 9.x^3+5x^2+3x-9
=(a^2+4a+4)-(b^2-2b+1) =x^2(x+3)+2x^2+3x-9
=(a+2)^2-(b-1)^2 =x^2(x+3)+(2x-3)(x+3)
=[(a+2)+(b-1)][(a+2)-(b-1)] =(x+3)(x^2+2x-3)
=(a+b+1)(a-b+3) = (x+3)(x-1)(x+3)
=(x+3)^2(x-1)
2. 9x^2-6x-y^2+4y-3
=(9X^2-6X+1)-(Y^2-4Y+4)
=(3X-1)^2-(Y-2)^2
=(3X-1+Y-2)(3X-1-Y+2)
=(3X+Y-3)(3X-Y+1)
3.x^2+5xy+x+3y+6y^2
=X^2+5XY+6Y^2+X+3Y
=（X+2Y)(X+3Y)+X+3Y
=(X+3Y）（X+2Y+1）
4.ab(a+b)^2-(a+b)^2+1
==a(a+b)*b(a+b)-(a+b)(a+b)+1
=a(a+b)*b(a+b)-a(a+b)-b(a+b)+1
=[a(a+b)-1][b(a+b)-1]
5.x^2-2x-2y^2+4y-xy
=(x^2-xy-2y^2)-(2x-4y)
=(x-2y)(x+y)-2(x-2y)
=(x-2y)(x+y-2)
6.〔x-2)^3-〔y-2)^3-〔x-y)*^3
=(x-2)^3+[(2-y)-(x-y)]*[(2-y)^2+(2-y)*(x-y)+(x-y)^2]
=(x-2)^3+(-x+2)*[(2-y)^2+(2-y)*(x-y)+(x-y)^2]
=(x-2){(x-2)^2-[(4-4y+y^2)+(2x-2y-xy+y^2)+(x^2-2xy+y^2)]
=(x-2)(x^2-4x+4-4+4y-y^2-2x+2y+xy-y^2-x^2+2xy-y^2)
=(x-2)(-6x+6y+3xy-3y^2)
=3(x-2)[-2(x-y)+y(x-y)]
=3(x-2)(y-2)(x-y)
7.x^4+x^3-3x^2-4x-4
=(x^4+x^3+x^2)-4x^2-4x-4
=x^2(x^2+x+1)-4(x^2+x+1)
=(x^2+x+1)(x^2-4)
=(x^2+x+1)(x+2)(x-2)
8.x(x-1)+y(y+1)-2xy
=x^2-2xy+y^2-x+y
=(x-y)^2-(x-y)
=(x + Y-1) (X-Y) fold up
Simplified evaluation: 1, 3A's Square - B's square + (2b-a) - (B's square + 3A's Square), where a = - 2, B = 1
2. 6xy-3 [the square of 3Y - (the square of x-2xy) + 1], where x = - 2, y = - 1 / 3
3. 1 / 4 (- square of 4x + 2x-8) - (1 / 2 x-1), where x = 1 / 2
4. The square of 5x - [(square of X + square of 5x - 2x) - 2 (square of X - 3x)], where x = - 0.5
5. Given the fourth power of (A-3) + A + B + 9 = 0, find the value of the square B of 3A - [the square B of 2A - (the square B of 2ab-a) - the square of 4A] - ab
6. Given the square of a = 8x, the square of y-6xy, - 3xy, the square of B = 7xy, - 2XY + the square of 5x, we can find the value of 2a-3b
1) 3 (x ^ 2-27) - 3 / 4 * x ^ 2
2) a^4-81
3) 11 (a-b) + 1 / 11 x (B-A) ^ 2
4) (x-y+2z)^2-(x-2y-3z)^2
5) x^2n-9^n
1) 3 (x ^ 2-27) - 3 / 4 * x ^ 2
First, take it apart
=3x ^ 2-3 * 27-3 / 4 * x ^ 2
Because 3x ^ 2 = 9x ^ 2 out of 3
So = 3 / 9x ^ 2-4 / 3 * x ^ 2-3 * 27
2) a^4-81
=(a^2)^2-9^2
Another formula a square minus b square
3) 11 (a-b) + 1 / 11 x (B-A) ^ 2
4) (x-y+2z)^2-(x-2y-3z)^2
5) x^2n-9^n
Simplify the following questions [the square of a, the square of B (3a-2b) (3a + 2b) - (- the square of-2ab)] / (- the square of a, the square of B)
Junior one factoring exercises, who is kind to help me solve
Denotes square
1.2X~-3XY-X
2.(X+Y)~(X+Y)(X-Y)(X+Y)(Y+Z)
3.3X(a+2b)~-6XY(a+2b)
4.a(x-y)-b(X-Y)-C(Y-X)
5.(b-a)~-2a+2b
6.(x-y)~-m(y-x)+y-x
7.x(x-y)(a-b)-y(y-x)(b-a)
8. Given a + B = 13, ab = 40, find the value of B + AB ~
1. Original formula = 3x ~ - 3xy-x ~ - x = 3x (X-Y) - x (x + 1) = x (3x-3y-x-1) = x (2x-3y-1) 3, original formula = 3x (a + 2b) ~ - 6xy (a + 2b) = 3x (a + 2b) (a + 2b-2y) 4, original formula = (a-b + C) (X-Y) 5, original formula = (B-A) (B-A + 2) 6, original formula = (X-Y) (x-y-m + 1) 7, original formula = (X-Y)! (a-b) 8, original formula = AB (a + b)
1. Original formula = 3x ~ - 3xy-x ~ - x = 3x (X-Y) - x (x + 1) = x (3x-3y-x-1) = x (2x-3y-1)
3. The original formula = 3x (a + 2b) ~ - 6xy (a + 2b) = 3x (a + 2b) (a + 2b-2y)
4. Original formula = (a-b + C) (X-Y)
5. Original formula = (B-A) (B-A + 2)
6. Original formula = (X-Y) (x-y-m + 1)
7. Original = (X-Y)! (a-b)
8. The original formula = AB (a + b) = 520
I didn't understand the second question