If the unitary linear equation AX2 + BX + C = 0 (a ≠ 0) satisfies 4a-2b + C = 0, then we call it the avatar equation. We know that AX2 + BX + C = 0 is the avatar equation A, a = C, B, a = B, C, B = C, a = B, B = C, B = C

If the unitary linear equation AX2 + BX + C = 0 (a ≠ 0) satisfies 4a-2b + C = 0, then we call it the avatar equation. We know that AX2 + BX + C = 0 is the avatar equation A, a = C, B, a = B, C, B = C, a = B, B = C, B = C

4a-2b+c=0,
b²-4ac=0
So: B & # 178; - 4a (2b-4a) = (b-4a) (B + 4a) = 0
That is, B = 4A or B = - 4A
In this case: 4a-8a + C = 0 or 4A + 8A + C = 0
That is: C = 4A or C = - 12a
=>B = C or B = 3C
=>C correct
SOS two univariate quadratic equations have the same root, find this root
If the equation x * X-6 * x-k-1 = 0 and X * x-k * X-7 = 0 have only one same real root, find the value of K and the same root
Let the same root be m
m^2-6m-k-1=0
m^2-km-7=0
By subtracting the two formulas, km-6m = K-6
m=(k-6)/(k-6)=1
That is, the same solution is 1, which is substituted into the equation to get 1-6-k-1 = 0
k=-6
Please write a linear equation of one variable which satisfies the following conditions at the same time. 1. The coefficient of an unknown is negative one-third. 2. The solution of the equation is negative four
(-1/3)x = 4/3
It is known that the coefficient of quadratic term of a bivariate equation is 3, and its two roots are - 2 / 3 and 4 respectively. Please write out the bivariate equation
Let the equation be: ax & # 178; + BX + C = 0
A=3
According to Weida's theorem:
-2/3+4=-b/a
∴b=-3×10/3=-10
(-2/3)×4=c/a
∴c=(-8/3)×3=-8
That is: the equation is: 3x & # 178; - 10x-8 = 0
From the meaning of the question, the quadratic equation of one variable can be written as follows:
3 (x + 2 / 3) (x-4) = 0
That is: (3x + 2) (x-4) = 0
That is: 3x square - 10x-8 = 0
ax^2+bx+c=0 , a=3
-2/3+4=-b/3 , -2+12=-b, b=-10
-8/3=c/3, c=-8
3x^2-10x-8=0
Write a linear equation of one variable, the coefficient of the unknown is negative half, the solution of the equation is 3
-1/2x=-3/2
-1\2x+ 3\2=0
-x/2-3/2=0
X=3
What is the relationship between root and coefficient in the equation of one variable
In a quadratic equation AX ^ 2 + BX + C (a is not equal to 0)
If there are roots X1 and X2
Then X1 + x2 = - B / A
x1*x2=c/a
Write a linear equation of one variable, so that the coefficient of the unknown - 3, the solution of the equation * = negative half, the equation is ()
-3x-3/2=0
-3x=3/2
-3x-1.5=0
Write out a quadratic equation of one variable so that the quadratic coefficient of the equation is 3, one root is - 4, and the other root is between 1 and 3
Y = 3x ^ 2 + BX + C get 0 = 3 × (- 4) ^ 2-4b + C, B = C / 4 + 12 get another 1 ＜ x ＜ 3, - 12 ＜ x1x2 = C / a = C / 3 ＜ - 4 get - 36 ＜ C ＜ - 12, get b = C / 4 + 12, and then you take a pleasing C to get quadratic function. Let C = - 24, then B = 6, y = 3x ^ 2 + 6x-24
Please write a linear equation with one variable so that its solution is - 3 / 5 and the coefficient of the unknown is a positive integer
5x+1=4,10x+2=8,20x-1=11
5X=3 10X=6
All the equations about C and Si in high school?
C + O2 = CO2, 2C + O2 = 2CO, C + CO2 = 2CO, C + 2CuO + 2Cu + CO2, CO + CuO = Cu + co23c + 2fe2o3 = 4