The set a = {1,3,2a}, B = {1, the square of a} asks whether there is such a real number a, such that B is contained in a, and a intersects B = {1, a}. If there is, the square of a is obtained

The set a = {1,3,2a}, B = {1, the square of a} asks whether there is such a real number a, such that B is contained in a, and a intersects B = {1, a}. If there is, the square of a is obtained

Because B is contained in a
So the square of a is 3
Or the square of a equals 2A
So the square of a = 2A
So a = 2 or a = 0
Given the set a = {x | x square + a ≤ a (a + 1)} if there is a real number a, the sum of all positive elements in the set a is 28
The sum of all positive integer elements in set a is 28
x^2 +a ≤a(a+1)
That is x ^ 2 ≤ a ^ 2
So - |a |≤ x ≤|a|
Obviously, 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28
Then the positive elements in set a are 1,2,3,4,5,6,7
And X ≤| a|
If | a | is greater than or equal to 8, then the positive element 8 will be generated
So | a|
1. If the square of X + MX-15 = (x + 3) (x + 3) (M + n), find the value of M and n
2. Factorization: (1) 4x square - 64
(2) Cubic multiplication of m by (A-2) + m (2-A)
(3) The fourth power of X - 8x square y square + 16y square
I need it urgently
1. The title is wrong;
2、=4(x²－4²)=4(x－4)(x＋4)；
3、=(a－2)m(m²－1)=m(m－1)(m＋1)(a－2)；
4、=(x²－4y²)²=(x－2y)²(x＋2y)².
One
x^2+mx-15=(x+3)(x+3)(m+n)
Decompose and merge the similar items
m=6(m+n)
9(m+n)=-15
M = - 10
n=25/3
2. 4X square - 64
=4(x²－4²)=4(x－4)(x＋4)；
3. Cubic multiplication of m by (A-2) + m (2-A)
=(A-2) m (M & sup2; - 1) = m (... Expansion)
One
x^2+mx-15=(x+3)(x+3)(m+n)
Decompose and merge the similar items
m=6(m+n)
9(m+n)=-15
M = - 10
n=25/3
2. 4X square - 64
=4(x²－4²)=4(x－4)(x＋4)；
3. Cubic multiplication of m by (A-2) + m (2-A)
=(a－2)m(m²－1)=m(m－1)(m＋1)(a－2)；
4. The fourth power of X - 8x square y square + 16y square
=(x²－4y²)²=(x－2y)²(x＋2y)²。
Is the correct solution, hope to adopt! Put it away
1、
x^2+mx-15=(x+3)(x+3)(m+n)
Decompose and merge the similar items
m=6(m+n)
9(m+n)=-15
M = - 10
n=25/3
2、
=4(x²－4²)=4(x－4)(x＋4)；
3、
=(a－2)m(m²－1)=m(m－1)(m＋1)(a－2)；
4、
=(x²－4y²)²=(x－2y)²(x＋2y)²。
1. The expansion on the right side: x ^ 2 + MX-15 = (M + n) x ^ 2 + 6 (M + n) x + 9 (M + n). The coefficients of corresponding terms are equal: M + n = 1,6 (M + n) = m, - 15 = 9 (M + n). The solution is: no solution, because m + n = 1 and - 15 = 9 (M + n) are contradictory.
2、（1）4（x+4）(x-4)
(2) m(a-2)(m+1)(m-1)
(3) (x^2-4y^2)^2=(x+2y)^2(x-2y)^2
The first question is wrong. After the = sign, it should be (x + 3) (X-5) (M + n) or (x-3) (x + 5) (M + n), which affects the value of M. the former is m = - 2, and the latter is m = 2. We can also know that M + n = 1, so n is 3 or - 1
Second question, first question: = 4 (x + 4) (x-4), extract the coefficient and use the square difference formula
Second, extract m (A-2) and then use the square difference formula, that is, the original formula = (A-2) * m * (M + 1) * (m-1)
The third sub topic is the complete square formula, the original formula = (x + 2Y) square product (... Expansion)
The first question is wrong. After the = sign, it should be (x + 3) (X-5) (M + n) or (x-3) (x + 5) (M + n), which affects the value of M. the former is m = - 2, and the latter is m = 2. We can also know that M + n = 1, so n is 3 or - 1
Second question, first question: = 4 (x + 4) (x-4), extract the coefficient and use the square difference formula
Second, extract m (A-2) and then use the square difference formula, that is, the original formula = (A-2) * m * (M + 1) * (m-1)
The third sub topic is the complete square formula. The original formula is the square of (x + 2Y) multiplied by the square of (x-2y)
Note: if the first question is not a clerical error, the above answer is correct. The following question is very simple, so the understanding may be wrong. Put it away
2.(1)4(x+4)(x-4)
(2)m(a+2)(m+1)(m-1)
(3)(x+2y)(x-2y)(x+2y)(x-2y)
1. Look at the coefficient of X & sup2;, the left coefficient is 1, and the right coefficient is m, then M + n = 1
If you look at the coefficient of X, the left coefficient is m, and the right coefficient is 6m + 6N, then M = 6m + 6N
If you look at the constant term, the left side is - 15 and the right side is 9m + 9N, then - 15 = 9m + 9N
The solution is m = - 10, n = 11
2. (1) 4x & sup2; - 64 = (2x) & sup2; - 8 & sup2; = (2x + 8) (2x-8) = 4 (X... expansion)
1. Look at the coefficient of X & sup2;, the left coefficient is 1, and the right coefficient is m, then M + n = 1
If you look at the coefficient of X, the left coefficient is m, and the right coefficient is 6m + 6N, then M = 6m + 6N
If you look at the constant term, the left side is - 15 and the right side is 9m + 9N, then - 15 = 9m + 9N
The solution is m = - 10, n = 11
2、（1）4x²-64=(2x)²-8²=(2x+8)(2x-8)=4(x+4)(x-4)
（2）m³(a-2)+m(2-a)=m³(a-2)-m(a-2)=(m³-m)(a-2)=m(m+1)(m-1)(a-2)
(3) (m²)²-8x²y²+(4y²)²=(m²-4y²)²=(m+2y)²(m-2y)²
I've been fighting for a long time. I hope you can understand it. happy everyday！ Put it away
1. Factorization, right = square of X + (n + 3) * x + 3 * n = quadratic of X + MX-15 = left.
By eliminating the common factor and merging the similar terms, we get (n-m + 3) * x + 3 * n + 15 = 0
Because the formula is always true, let x = 0 and N = - 5. Then the above formula becomes (2 + m) * x = 0, let x = 1, and M = - 2
To sum up, M = - 2
2. (1) the square-64 factorization of 4x
Calculate the second power of (2a-5b) and the second power of - (2a + 5b)
1. (2a-5b) to the second power - (2a + 5b) to the second power
2. (P-3) to the second power - (P + 3) (P-3)
1. (2a-5b) to the second power - (2a + 5b) to the second power
=（2a-5b+2a+5b)(2a-5b-2a-5b)
=4a×(-10b)
=-40ab
2. (P-3) to the second power - (P + 3) (P-3)
=(p-3)[(p-3)-(p+3)]
=-6(p-3)
=-6p+18
The square difference formula of the first question is equal to - 40ab
The second question is to extract the common factor equal to 18-6p
1. (2a-5b)^2-(2a+5b)^2
=4a^2-20ab+25b^2-(4a^2+20ab+25b^2)
=-40ab
2. (p-3)^2-(p+3)(p-3)
=(p-3)[(p-3)-(p+3)]
=-6(p-3)
=6(3-p)
|2a-1 | + [(5b-6) to the second power] = 0
Because | 2a-1 | and (5b-6) ^ 2 are both nonnegative numbers, they can only be 0.
So 2a-1 = 0, that is, a = 1 / 2
5b-6 = 0, that is, B = 6 / 5
So 2A + 5B = 2 * 1 / 2 + 5 * 6 / 5 = 1 + 6 = 7
On factorization
If x ^ 3-3x ^ 2 + ax-9 can be divided by x-3, then the value of a is________
Let f (x) = x ^ 3-3x ^ 2 + ax-9
The remainder theorem, f (3) = 0
So a = 3
If | 2a-1 | + [(5b-6) quadratic] = 0, then 2A + 5B = what?
|2a-1 | + [(5b-6) to the second power] = 0
Because | 2a-1 | and (5b-6) ^ 2 are both nonnegative numbers, they can only be 0
So 2a-1 = 0, that is, a = 1 / 2
5b-6 = 0, that is, B = 6 / 5
So 2A + 5B = 2 * 1 / 2 + 5 * 6 / 5 = 1 + 6 = 7
|2a-1 | + [(5b-6) quadratic] = 0, then 2A + 5B = 7
Please list all the formulas of multiplication and division of integers and factorization in Volume 1 of Grade 8, thank you~~~~~~~~~~~~
That's all
(1) Square difference formula: A ^ 2-B ^ 2 = (a + b) (a-b)
(2) Complete square formula: (a-b) ^ 2 = a ^ 2-2ab + B ^ 2, (a + b) ^ 2 = a ^ 2 + 2Ab + B ^ 2
(3) Cubic difference formula: A ^ 3-B ^ 3 = (a-b) (a ^ 2 + AB + B ^ 2)
(4) Cubic sum formula: A ^ 3 + B ^ 3 = (a + b) (a ^ 2-AB + B ^ 2)
It is necessary to master these formulas in middle school
Square difference formula
Complete square formula
PQ formula
Term splitting formula
formula
Factorization (a + b) = A & sup2; + B & sup2; + 2Ab
（a-b）=a²+b²-2ab
（a+b）（a-b）=a²-b²
（a+x）（a+y）=a²+（x+y）+a+xy
It is known that the a power of M is 10, the B power of M is 14, the a + B of M is several, and the 2A power of M is several
A + B of M
=m^a*m^b
=10*14
=140
m^2a
=(m^a)^2
=10^2
=100
Requirements|
The 5th power of a = the 4th power of B, the 3rd power of C = the 2nd power of D, a-c = 19, how much d-c =
If a ^ 5 = B ^ 4 (B / a) ^ 4 = a, let B / a = x, then a = x ^ 4C ^ 3 = D ^ 2 (D / C) ^ 2 = C, let D / C = YC = y ^ 2a-c = 19, so x ^ 4-y ^ 2 = (x ^ 2 + y) (x ^ 2-y) = 19 = 19 * 1y > 0, so x ^ 2 + Y > x ^ 2-y, so x ^ 2 + y = 19x ^ 2-y = 1, so x ^ 2 = 10, y = 9, should be D-B? A = x ^ 4, a ^ 5 = B ^ 4, so x ^ 20 = B ^ 4, so B = x ^ 5
Merge the square B of 2A minus the square of 3AB plus 3a, square B plus 6 minus one third, and the square of AB minus 1
2ab-3ab+3ab+6-1/3ab-1=（2+3）ab-（3+1/3) ab+(6-1)=5 ab-10/3 ab+5