How to factorize a ^ 4-b ^ 4 Factorization

How to factorize a ^ 4-b ^ 4 Factorization

Because a ^ 2-B ^ 2 can be factorized~~~
Factorization of the following formula: (a + b) ^ 2-4 [(a + b) - 1] =?
(a+b)^2-4[(a+b)-1]
=(a+b)^2-4(a+b)+4
=(a+b-2)^2
(a+b)^2-4[(a+b)-1]=(a+b)^2-4(a+b)+4=(a+b-2)^2
Factorization of a ^ 4-A ^ 2
a^2（a+1）（a-1）
A mathematical problem of quadratic equation of two variables
If you put some chickens in several cages, if you put 4 chickens in each cage, there will be one chicken without cage. If you put 5 chickens in each cage, there will be one cage without chicken. How many cages, how many chickens?
Chicken x
Then x / 4-1 = x / 5 + 1
We get x = 40,
Cage 40 / 4-1 = 9
Set X cages and Y chickens
4x+1=y
5（x-1）=y
4x+1=5x-5
x=6,y=25
(high score) given x2-3x + 1 = 0, find the value of the following formula
Given x2-3x + 1 = 0, find the value of the following formula:
(1) (2) x2 + 1 / 2 (3) the fourth power of X + x2 + 1 / 2
It's not good, but you'll understand if you're smart!,
Given x ^ 2-3x + 1 = 0, find the value of Ou as follows: (1) the value of 1 / 2 of X; (2) x ^ 2 + x ^ 2 (3) the fourth power of X + x ^ 2 + 1 / x2 by x ^ 2-3x + 1 = 0, x-3 + 1 / x = 0,1), that is, x + 1 / x = 3,2) divide (x + 1 / x) ^ 2 = 3 ^ 2, x ^ 2 + 2 + 1 / x ^ 2 = 9, so x ^ 2 + 1 / x ^ 2 = 7,3) by X ^ 2
X^2-3X+1=0
x-3+1/x=0
x+1/x=3
x^2+1/x^2
=(x+1/x)^2-2
=3^2-2
=9-2
=7
x^2-3x+1=0
X ^ 2 + 1 = 3x (square)
x^4+2x^2+1=9x^2
x^4+x^2+1=8x^2
x^2/(x^4+x^2+1)=8
(1)x^2+1=3x x+1/x=3
(2)x^2+1/x^2=(x+1/x)^2-2=9-2=7
(3)x^2/(x^4+x^2+1)=1/(x^2+1/x^2+1)=1/(7+1)=1/8
2x-3x + 1 = 0,2x-3x = - 1, x = 1,1
1. 1 of X + x = (x ^ 2 + 1) / x = 3 x ^ 2 + 1 = 3x
2. One of x2 + x2 = (x + 1 / x) ^ 2-2 = 9-2 = 7
3. The fourth power of X + x2 + 1: x2 = x ^ 2 / (x ^ 4 + 3x) = x / (x ^ 3 + 3) x2-3x + 1 = 0 x ^ 3 = 3x ^ 2-x
... unfold
1. 1 of X + x = (x ^ 2 + 1) / x = 3 x ^ 2 + 1 = 3x
2. One of x2 + x2 = (x + 1 / x) ^ 2-2 = 9-2 = 7
3. The fourth power of X + x2 + 1: x2 = x ^ 2 / (x ^ 4 + 3x) = x / (x ^ 3 + 3) x2-3x + 1 = 0 x ^ 3 = 3x ^ 2-x
=x/(3x^2+3-x)
=x/[3(x^2+1)-x]
=x/(9x-x)
=1 / 8 "put away
(1) 2
(2) 2.25
(3) 20
Because 2x-3x is - 1 to satisfy the equation, so x = 1, then (1) is 1 + 1 = 2
(2) That's 2 + 1 / 4 = 2.25
(3) It's 2 times 2 times 2 times 2 = 16 + 2 times 1 + 1 / 2 = 20
X2-3X+1=0
x-3+1/x=0
x+1/x=3
x^2+1/x^2=(x+1/x)^2-2=3^2-2=7
x^2/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/[(x^2+1/x^2)+1]=1/(7+1)=1/8
What a tangled topic ~ ~ ~ I'm about to throw up ~ ~ ~ hey, let me tell you first, x = ± root 5 + 3 divided by 2 ~ ~ ~ hey, stupid way, I can't figure it out, I'll think about it~~~
The front row is so strong ~ ~ ~ dig a hole ~ ~ ~ hide~~~
Solving a mathematical problem of quadratic equation of two variables
The distance between the two places is 320 kilometers, and a ship sails between them. It takes 20 hours to go downstream and 40 hours to go upstream. The speed of the ball ship in the purified water and the water flow speed
I'll help you with the equations
The velocity in the purified water is x and the flow velocity is y
320=20*(x+y)
320=40*（x-y）
The results show that x + y = 2x-2y, x = 3Y
So the original equation is 320 = 80y
Y=4
x=12
Let the velocity of the spherical vessel in the purified water be x km / h and the velocity of the water flow be y km / h
Then 20 (x + y) = 320
40（x-y）=320
The solution is x = 12, y = 4
Let the ship speed be x and the water speed be y.
Downstream: (x + y) * 20 = 320
Countercurrent: (X-Y) * 40 = 320
Stiffness x = 12, y = 4
12 4
Let the velocity of the ship in the purified water be x and the velocity of the water be y
20(X+Y)=320
40(X-Y)=320
Let the water speed be x and the ship speed be y, then 20x + 20Y = 320; 40x-40y = 320;
That is x + y = 16 (1) X-Y = 8 (2) (1) + (2)
X=12； Y=4
Mathematics problem (x-1) / x2-3x-4 x tends to 1. What is the limit? The answer is 1 / 5 problem solving process
Eager for an answer..
(X-1)/X^2-3X-4=(X-1)/(X-1)(X+4)=1/(X+4);(X≠1,≠-4)
(x-1) / x2-3x-4 x tends to 1, and the limit = 1 / 5
Your topic is wrong. It should be (x-1) / x2 + 3x-4. Decompose the denominator factor (x-1) (x + 4) into 1 / x + 4. When x approaches 1, it is 1 / 5
The answer is satisfactory...
A mathematical problem of quadratic equation of two variables
4 = y & # 178; X (Y - √ 2) &# 178;
Ask the master to solve the problem detailed process and ideas, thank you
[reference answer]
Firstly, the equation is simplified
4 = y & # 178; X (Y - √ 2) &# 178;
4=y²+y²-2√2 y+2
2y²-2√2 y-2=0
y²-√2 y-1=0
Using the root formula to find the root
∵△=(√2）²+4=6
∴ y1=(√2 +√6)/2
y2=(√2 -√6)/2
4 = y² + (y - √2)²
4 = y² + (y² - 2√2y + 2)
2y² - 2√2y - 2 = 0
y = {2√2 ± √[(- 2√2)² - 4(2)(- 2)]}/(2*2)
= (2√2 ± 2√6)/4
= (√2 ± √6)/2
4 = y² + (y - √2)²
4 = y² + (y² - 2√2y + 2)
2y² - 2√2y +2 = 4
y² - √2y -1= 0
y = {√2 ± √[2 + 4]}/2
= (√2 ± √6)/2
Mathematics problem when x
f(x)=(x²-3x+1)/(x+1)
=(x²+x-4x-4+5)/(x+1)
=[x(x+1)-4(x+1)+5]/(x+1)
=x-4+5/(x+1)
=x+1+5/(x+1)-5
X
A mathematical problem about quadratic equation of two variables
Each train of a and B is 180m long. If the two trains run in opposite directions, it takes 12 seconds from the front to the rear,
If two trains are traveling in the same direction, it will take 60 seconds from the front of a to the rear of B until the rear of a exceeds the front of B. assuming that the speed of the train remains the same, try to find the speed of a and B
We should use the solution of quadratic equation of two variables
Let both be x / s and Y / s
12(x+y)=360
60(x-y)=360
60x+60y=1800
60x-60y=360
120x=2160
x=18 y=12