Let u = {positive integers no more than 5}, a = {x | x2 ^ - 5x + M = 0}, B = {x | x2 ^ + NX + 12 = 0}, and (CUA) ∪ B = {1,3,4,5}, B ≠ empty set, find the value of real number m + n

Let u = {positive integers no more than 5}, a = {x | x2 ^ - 5x + M = 0}, B = {x | x2 ^ + NX + 12 = 0}, and (CUA) ∪ B = {1,3,4,5}, B ≠ empty set, find the value of real number m + n

(CuA)∪B={1,3,4,5}
2∈A
So m = 6
A={2,3}
CuA={1,4,5}
So 3 must be ∈ B
n=-7
So m + n = - 1
U = {1,2,3,4,5}. Because (CUA) ∪ B = {1,3,4,5}, there is element 2 in set A. substituting x = 2 into x2 ^ - 5x + M = 0, M = 6 is obtained. The solution is a = {2,3}
So there is element 3 in B, and the solution is n = - 7
First of all, if we know that the number 2 is neither in CUA nor B, then it must be in a
Substituting 2 into a, M = 6. Solving a again, a = {2,3}, then CUA is {1,4,5}
So 3 must be in B, substituting B to get n = - 7
So m + n = - 1
Let u = {1.2.3.4.5}, a = {x ∈ u | x ^ 2-5x + q = 0}, find the value of Q and the complement of A
Because a = {x ∈ u | x ^ 2-5x + q = 0}, we can get: X1 + x2 = 5, X1 * x2 = Q. we can get: X1 = 1, X2 = 4, q = 4;
Or X1 = 2, X2 = 3, q = 6. Then a = {1,2,3,4}
The complement of a = {5}. Q = 4 or 6
The factorization method must be used to solve the quadratic equation of one variable. The specific process is needed. Thank you~
Square of 1 / 2x + 7 / 2x + 5 = 0
-The square of X + 3x + 8 = 0
Square of 1 / 2x + 7 / 2x + 5 = 01 / 2 (X & # 178; + 7x + 10) = 01 / 2 (x + 2) (x + 5) = 0x + 2 = 0, x + 5 = 0x1 = - 2, square of x2 = - 5-x + 3x + 8 = 0 - (X & # 178; - 3x-8) = 0 - [x - (3 + √ 41) / 2] [x - (3 - √ 41) / 2] = 0x - (3 + √ 41) / 2 = 0, X - (3 - √ 41) / 2 = 0x1 = (3 + √ 4
Square of 1 / 2x + 7 / 2x + 5 = 0
x^2+7x+10=0
(x+2)(x+5)=0
x=-2 x=-5
-The square of X + 3x + 8 = 0
x^2-3x-8=0
This problem is wrong, can't factorize, can use formula method or match method to solve equation
x(4x+1)²-3x(4x+1)=0
x(4x+1)²-3x(4x+1)=0
16x^3+8x^2+x-12x^2-3x=0
16x^3-4x^2-2x=0
8x^3-2x^2-x=0
① When x = 0, it holds
② When x ≠ 0, eliminate x, 8x ^ 2-2x-1 = 0
We get (4x + 1) (2x-1) = 0
X = - 1 / 4 or 1 / 2
To sum up, the roots of the equation are 0, - 1 / 4, 1 / 2
To transform the unknown into known, that is to say, to transform the binary system of first-order equations into a system of first-order equations through elimination, the basic method is method or method
Addition subtraction elimination method and substitution elimination method
Thank you
(x-y-3) & #178; and | 4x-3x = 11 | are opposite to each other, and x =? Y =?
The title should be (x-y-3) & #178; and | 4x-3y + 11 | opposite to each other
(x-y-3)²+|4x-3y+11|=0
x-y-3=0 （1）
x=y+3
4x-3y+11=0 （2）
4(y+3)-3y+11=0
4y+12-3y+11=0
y=-23
x=-20
Both of them can only be 0, and the connection equation is solved
The basic idea of addition subtraction elimination method in solving binary linear equations
First, make the coefficient of an unknown term the same by multiplication and division, then subtract
1. {5 > 2 (1-x) - 1 / 3x is less than or equal to 2, 3-x 2. {5x + 6 > 4x, 15-9x is less than or equal to 10-4x
1.｛5>2(1-x)
-1 / 3x less than or equal to 2,3-x
2.{5x+6>4x
15-9x less than or equal to 10-4x
The first problem is. {5 > 2 (1-x)
Negative 1 / 3x less than or equal to 2 / 3-x
Is it a system of inequalities or an equation? The solution of 5 > 2 (1-x) is: x > - 2 / 3 negative 1 / 3x is less than or equal to 2 / 3-x, and the solution is: X ≤ 1
The solution of 5x + 6 > 4x is: x > - 6, 15-9x is less than or equal to 10-4x, and the solution of X is greater than or equal to 1
5> The solution of 2 (1-x) is: x > - 3 / 2
-1 / 3x is less than or equal to 2, 3-x??? I don't understand
The solution of 5x + 6 > 4x is: x > - 6
The solution of 15-9x less than or equal to 10-4x is that x is greater than or equal to 1
It's hard. I have a headache
I didn't understand the title
The basic idea of solving the system of linear equations of two variables is, that is to change the system of linear equations of two variables into
The basic idea of solving binary linear equations is (elimination), that is, transforming binary linear equations into (one variable linear equations)
If the square of X + 3x + 7 is 8, find the cube of X + 4x square + 2x-7
x²+3x+7=8
x²+3x=1
Cube of X + square of 4x + 2x-7
=x(x²+3x)+x²+2x-7
=x+x²+2x-7
=x²+3x-7
=1-7
=-6
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