If the two real roots of the square of x-3x + 1 = 0 are X1 and X2, then the value of 1 / 10 of X1 and 1 / 10 of X2 is?

If the two real roots of the square of x-3x + 1 = 0 are X1 and X2, then the value of 1 / 10 of X1 and 1 / 10 of X2 is?

The two real roots of the square of X - 3x + 1 = 0 are X1 and x2
According to Weida's theorem
x1+x2=3 ,x1*x2=1
that
1/x1+1/x2
=(x2+x1)/(x1x2)
=3/1
=3
Let X1 and X2 be the two roots of the equation 2x with square-5x-6 = 0, and find the value of 1 / 2 of X1 + 1 / 2 of x2
According to the meaning of the title, we get the X1 + x2 = 5 / 2 X1 x2 = - 3, so 1 / X & 35;35;35353535353535\\\\\\35\35\\35\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\178; / (- 3) & 178; - 2 = 25 / 36-2 = - 47 / 32
(1) Let two of the equations x + 5x = 2 be x1, X2, then x2 of x1-1 + X1 of x2-1 = (2) if
(1) Let two of the equations x + 5x = 2 be x 1, x 2, then x 1-1 / x 2 + X 2-1 / x 1=
(2) If the absolute values of the radical x-2y + 9 and X + Y-3 are opposite to each other, then x = y=
(3) If the ratio of the two parts of the equation AX square + BX + C = 0 (a ≠ 0) is 1:3, then the relationship between a, B and C is ()
A3bc = 4A square B3b square = 16ac
CB squared = 4ac D2B squared = 4A squared C
Why choose that
(4) If the equation x-4x + M = 0 has the same root as x-x-2m = 0, then the value of M is
A3 B-3 C0 d0 or 3
(explain why)
(1) X ^ 2 + 5x = 2 x ^ 2 + 5x-2 = 0 x1x2 = - 2 X1 + x2 = - 5 x2 / (x1-1) + X1 / (x2-1) = (2x1x2 - (x1 + x2)) / (x1x2 + 1 - (x1 + x2)) = (2x-2 -- 5) / (- 2 + 1 -- 5) = 3 / 2 (2) radical x-2y + 9 = x + Y-3 = 0 x = - 1 y = 4 (3) B (4) d
Ternary linear equations of grade one in junior high school
5y=3x
7z=3x
2x-y-z=34
How to solve this cubic equation
5y=3x y=3x/5
7z=3x z=3x/7
So 2x-y-z = 34 can be reduced to
2x - 3x/5 - 3x/7=34
The solution is x = 35
So y = 3 * 35 / 5 = 21
z=3*35/7=15
y=3/5x
z=3/7x
2x-3/5x-3/7x=34
x=35
y=21
z=15
5Y = 3x, so y = 3x / 5
7z = 3x, so z = 3x / 7
Substituting 2x-y-z = 34
2x-3x/5-3x/7=34
34x/35=34
x=35
y=3x/5=21
z=3x/7=15
Substituting z = 3 / 7X, y = 3 / 5x into formula 3
2X-3/7X-3/5X=34 X=35
That is, y = 21, z = 15
Y = 3 / 5x
z=3/7x
Substituting
2x-3/5x-3/7x=34
x=35
y=21
z=15
x=35
y=21
z=15
x=35
Y=3/5X
Z=3/7X
2X-3/5X-3/7X=34
X=35
Y=21
Z=15
It is known that when x = 2, the minimum value of the parabola y = ax & # 178; + BX + C is - 1, and the parabola intersects the y-axis at point C (0,3) and the x-axis at points a and B
(1) Find the relation of the parabola
(2) If the points m (x, Y1), n (x + 1, Y2) are all on the parabola, try to compare the size of Y1 and Y2
(3) D is the midpoint of the line AC, e is a moving point on the line AC (except for the points at both ends of a and C), and a parallel line EF passing through point e along the Y axis intersects with a parabola at point F. question: is there any similarity between △ def and △ AOC? If so, find out the coordinates of point E. if not, explain the reason
No money
Yes, here is the answer
A testing station needs to test a batch of instruments within the specified time. Originally, it planned to test 30 instruments a day, but it can only complete 4 / 5 of the total within the specified time. Now, it actually tests 40 instruments a day, not only completing the task one day ahead of the original plan, but also testing 25 more instruments. How many days is the specified time? How many instruments are there in total?
The original plan takes X days, and the total number is y units
30x=4/5y
40（x-1）=y+25
We get x = 26
y=975
30*d=S*(4/5)
40*(d-1)=S+25
D=
S=
Given that the parabola y = ax & # 178; + BX + C passes through the point (- 1,3), and when x = 1, there is a minimum value of - 5, find the analytical formula of the parabola
Let y = a (x + m) ² + K,
When x = 1, there is a minimum value of - 5,
∴m=-1,k=-5,
We get y = a (x-1) ² - 5 and substitute (- 1,3) into the result
4a-5=3,
∴a=2,
∴y=2(x-1)²-5
That is y = 2x & # 178; - 4x-3
The expert solution of ternary linear equations in grade one mathematics of junior high school
1、x+y+z=2 3x-y-4z=5 2x+3y-2z=0 2、2x+3y+z=38 3x+4y+2z=56 4x+5y+z=66
1、x+y+z=2 (1)
3x-y-4z=5 (2)
2x+3y-2z=0 (3)
(1) + (2) get
4x-3z=7 (4)
(1) * 3 - (3) de
x+5z=6
x=6-5z
Substitute the above formula into (4)
4（6-5z)-3z=7
24-20z-3z=7
23z=17
z=17/23
x=53/23
y=-24/23
2、2x+3y+z=38 (1）
3x+4y+2z=56 （2）
4x+5y+z=66 (3)
(1) * 2 - (3) de
x+2y=20 (4）
(3) * 2 - (2) de
5x+6y=76 (5)
(5) - (4) * 3
2x=16
X=8
Y=6
Z=4
The parabola y is equal to a times the square of x plus B and the parabola y is equal to 3x square plus 1. How to find the value of a and B with respect to X-axis symmetry
-3, - 1 with respect to X-axis symmetry, X is invariant, and Y becomes its opposite number. Then y equals 3x square plus 1, and becomes 3x square = Y-1 with respect to X-axis symmetry, X is invariant, and Y becomes its opposite number. Then 3x square = Y-1 becomes 3x square = - Y-1. So there is y = - 3x Square-1
A good way to solve equations. (one variable and two variable)
One variable once: 1. Remove the denominator and multiply the least common multiple of the denominators on both sides at the same time. 2. Remove the brackets and use the law of distribution by multiplication. 3. Move the term to one side of the equation, and move the term without letter to the other side. 4. Combine the similar terms and add the coefficients of the similar terms to make the equation into the form of AX = B