Given x = - 6, y = one third, find one sixth of 3x + XY x + 3Y ^ 2 + 10

Given x = - 6, y = one third, find one sixth of 3x + XY x + 3Y ^ 2 + 10

=[1/6×(-6)+3×(1/3)²+10]/[3×(-6)+(-6)×(1/3)]
=(-1+1/3+10)/(-18-2)
=(28/3)/(-20)
=-7/15
Can a function like y = 3 * X-1 / 2 + sqrt (x ^ 2-3x-5) find the maximum or minimum?
I am now in junior three, it is said that high school will learn to find this kind of function extremum method
Theoretically, it is possible to find the derivative of the function y. I learned to find the derivative of a function in senior high school. According to the derivation, I can solve such problems
If 4x-3y = 0, the value of 4x − 5y4x + 5Y is ()
A. 14B. −14C. 12D. −12
1/2x,-2/3x^2,3/4x^3,-4/5x^4,5/6x^5…… Write the 10th? Nth?
(-1)^(n-1)●n/(n+1)x^n
7x-3y=-1 10x+3y+1=0 4x-5y=-17 4x+5y+8=0
7x-3y=-1 10x+3y+1=0
4x-5y=-17 4x+5y+8=0
linear equation in two unknowns
Please write down the steps
From 7x-3y + 1 = 0, there is x = (3y-1) / 7
4x-5y = - 17
We get x = 2
Y=5
Decomposition factor: 4x ^ 2-31x + 1542 x ^ 5 + X + 1 x ^ 3 + 5x ^ 2 + 3x-9
x^5+x+1
＝x^5-x^2+x^2+x+1
=x^2(x^3-1)+(x^2+x+1)
=x^2*(x-1)(x^2+x+1)+(x^2+x+1)
=(x^2+x+1)(x^3-x^2+1)
x^3+5x^2+3x-9
=(x^3-1)+(5x^2+3x-8)
=(x-1)(x^2+x+1)+(5x+8)(x-1)
=(x-1)(x^2+x+1+5x+8)
=(x-1)(x^2+6x+9)
=(x-1)(x+3)^2
The square of X - (4x + 5Y) (4x-5y) + - 2x-7y
=x²-16x²+25y²+4x²+28xy+49y²
=-11x²+28xy+83y²
Simplify 18m-5n - [20m - (3n-6)] - 2 (2m + N + 3) 2x - {- 3Y + [4x - (3x-y)])
（1） 18m-5n-[20m-（3n-6）]-2（2m+n+3) （2） 2x-｛-3y+[4x-（3x-y）]｝
1 -6m-4n-12
2 x+2y
If 3x 5Y 6 = 0 and 3x y-7z = 0, what is the value of X + y + Z?
If 3x + 5Y + 6 = 0, 3x + y-7z = 0, then what's the value of X + y + Z? Come on!
3x + 5Y + 6 = 0, 3x + y-7z = 0, so 3x + 5Y + 6 + 3x + y-7z = 0, 6x + 6y-7z = - 6x + y = - 7z / 6x + y + Z = - Z / 6, I want to ask, have you written the wrong topic
Given that 3x + 6 and 2x + 9 are opposite numbers, try to find the value of X
What is x equal to
If the numbers are opposite to each other, they add up to 0
So 3x + 6 + 2x + 9 = 0
5x=-15
x=-3