Given that X and Y in the system of equations 2x-5y = - 3 - 4x + y = - 3 are opposite to each other, M can be obtained

Given that X and Y in the system of equations 2x-5y = - 3 - 4x + y = - 3 are opposite to each other, M can be obtained

2mx-5y= -3
-4mx+y= -3,x=-y
-2my-5y=-3 ,y=3/(2m+5)
4my+y=-3 ,12/(2m+5)+3/(2m+5)=-3 ,5=-(2m+5) ,m=-5
2x-5my= -3
-4x+ym= -3,x=-y
2x+5mx=-3
-4x-mx=-3,x=3/(m+4) ,6/(m+4)+15/(m+4)=-3 ,7=-m-4,m=-11
M has different solutions in different positions
How to solve the equation 2x + 3 = 3x?
2x+3=3x
3=3x-2x
X=3
Move 2x to the back of 3x (remember to change the sign when moving) to 3 = 3x-2x, and simplify to 3 = X~
3x-2x = 3
The solution is x = 3
Solve the equations 2x-3y = 5,4x-5y = 9
2x-3y=5 .(1)
4x-5y=9.(2)
(2) - 2 × (1)
x=1,y=-1
Multiply equation 1 by 2 and subtract equation 2 to get - y = 1, so y = - 1. Bring y = - 1 into equation 2 to get x = 1
2x=3y+5 2(3y+5)-5y=9 6y+10-5y=9 y=-1 x=1
Solution equation: 2x / 5 + 1 / 3 * (3x / 5) + 3 / 4 * (3x / 5 * (1-1 / 3) = X-15
Better step by step
2x/5+1/3*(3x/5)+3/4*(3x/5*(1-1/3)=x-15
2x/5+x/5+3/4*(3x/5*(2/3)=x-15.
3x/5+3/4*(2x/5)=x-15.
3x/5+3x/10=x-15.
Multiply both sides by 10 to get
6x+3x=10x-150
10x-9x=150
x=150
The original formula can be reduced to: 2x / 5 + X / 5 + 3 / 4 * (3x / 5-x / 5) = X-15
3x/5+9x/20-3x/20=x-15
18x/20=x-15
1x/10=15
x=150
The distance between two parallel 3x + 2y-1 = 0 and 6x + 4Y + 1 = 0 is____
I kind of want to beat you up
3X + 2Y -1 = 0
6X + 4Y +1 = 0 => 3X +2Y +0.5=0
According to the formula, (0.5 - (- 1)) is 1.5
Remove 1.5 and add the square of 2 to the square of 3 under the root
The point (1, - 1) is on the line 3x + 2y-1 = 0
The distance from it to the straight line 6x + 4Y + 1 = 0 is d = | 6-4 + 1 | / radical (36 + 16) = 3 / radical 52
=3 roots 13 / 26
Solution equation: 5 * 2x = 4 * (3x-15)
It is known that 5 * 2x = 4 * (3x-15),
10x=12x-60
12x-10x=60
2x=60
x=30
5*2x=4*(3x-15)
10x=12x-60
2x=60
x=30
Find the linear equation which is parallel to the line 3x + 2y-6 = 0 and the sum of intercept on two coordinate axes is - 2
Let this line be: 3x + 2Y = C
Then, X / (C / 3) + Y / (C / 2) = 1
So the distance between the two axes is: C / 3, C / 2
c/3+c/2=-2
c=-12/5.
3x+2y=-12/5
15x+10y+12=0.
Solution equation: 2 (X-2) (x + 3) - (2x-5) (x-1) = 3x + 7
2（x-2)(x+3)-(2x-5)(x-1)=3x+7
2（x²+x-6）-（2x²-7x+5）=3x+7
2x²+2x-12-2x²+7x-5=3x+7
9x-17=3x+7
6x=24
X=4
2x^2+2x-12-(2x^2-7x+5)=3x+7
9x-17=3x+7
6x=24
X=4
If the difference between the intercept of the line 3x + 2Y + k = 0 on the two axes is 3, the equation of the line is solved
Let x = 0, the longitudinal intercept is - K / 2
Let y = 0, and the intercept is - K / 3
So there is - K / 2 + K / 3 = 3 or - K / 3 + K / 2 = 3
The solution is k = - 18 or 18
So the linear equation is 3x + 2Y ± 18 = 0
A:
3x+2y+k=0
When x = 0: y = - K / 2
When y = 0: x = - K / 3
According to the meaning of the title:
|-k/2-(-k/3)|=3
So: | - K / 6 | = 3
So: | K | = 18
The solution is: k = - 18 or K = 18
Known: integer x satisfies y = X-2 √ 3x-1 - √ 5-2x, find the value of Y
Greater than or equal to 0 under root sign
3x-1>=0,5-2x>=0
1/3