First question: 5x-4y = 12 y-5x = 7 find x y value second question: 5x-2y = 10 3x-5y = 2 find x y value Question 3: 5 (x-1) - 2 (Y-2) = 10 Question 4: 3x + 4Y = 2 (Y-1) Thank you, there should be a process, oh, urgent..... Sorry for the inconvenience

First question: 5x-4y = 12 y-5x = 7 find x y value second question: 5x-2y = 10 3x-5y = 2 find x y value Question 3: 5 (x-1) - 2 (Y-2) = 10 Question 4: 3x + 4Y = 2 (Y-1) Thank you, there should be a process, oh, urgent..... Sorry for the inconvenience

Question 1 x = - 8 / 3 y = - 19 / 3
Question 2 x = 46 / 21 y = 10 / 21
Bivariate linear equation: elimination method
Question 3 x = 9 / 8 y = - 43 / 16
In the first question, x = - 8 / 3, y = - 19 / 3, in the second question, x = 46 / 19, y = 20 / 19
Finding the minimum value of quadratic function y = 1 / 2x & sup2; + 2x + 1 / 2
y=1/2x²+2x+1/2
y=1/2(x²+4x+1)
y=1/2(x²+4x+4-3)
y=1/2(x+2)²-3/2
Then, when x = - 2, y has a minimum value of - 3 / 2
-2 into y
2-4+1/2=-3/2
Far better than her
[(x + 3Y) (x-3y) - 6 / 1 (2x-3y) (3x + 6y)] / (4 / 1), where x = - 2, y = 8 / 1
Original formula = (X & # 178; - 9y & # 178; - 6 / 1 (6x & # 178; + 3xy-18y & # 178;) × 4
=(x²-9y²-x²-2/1xy+3y²)×4
=4(-2/1xy-6y²)
=-2xy-24y²
When x=______ The quadratic function y = x2 + 2x-2 has a minimum value, and its minimum value is______ .
∵ the quadratic function y = x2 + 2x-2 can be reduced to y = (x + 1) 2-3, when x = - 1, the quadratic function y = x2 + 2x-2 has the minimum value of - 3, so the answers are: - 1, - 3
Given that | x + 3y-5 | and | 3x-6y-6 | are opposite numbers, what is the value of 2x + 3Y?
If the formulas with absolute values are all nonnegative, then the two nonnegative numbers are opposite to each other, then they must be equal to 0, so we can get two equations about X and y, so 3x-6y-6 = 0, x + 3y-5 = 0, and the solution is x = 16 / 5, y = 3 / 5, so 2x + 3Y = 32 / 5 + 9 / 5 = 41 / 5
X + 3y-5 = 0, and 3x-6y-6 = 0
be
y=3/5
x=16/5
Given 3x-4y / 2x + y = 1 / 2, find the value of X / y
proportion
3x-4y/2x+y=1/2
6x-8y=2x+y
4x=9y
x/y=9/4
3x-4y/2x+y=1/2
6x-8y=2x+y
4x=9y
x/y=9/4
If the solution of the binary linear simultaneous equation 2x − 3Y6 = 415x + 15y − 53 = 0 is x = a, y = B, then A-B = ()
A. 53B. 95C. 293D. −1393
Firstly, by simplifying the equations, we get 2x − 3Y = 24, ① 3x + 3Y − 1 = 0, ② ① + ②, we get 5x = 25, that is, x = 5. Y = - 143. ∵ x = a, y = B, ∵ A-B = X-Y = 5 - (- 143) = 293
Solving equation | 2x-3 | = 3x-1
|2x-3|=3x-1
2x-3 = 3x-1 or 2x-3 = - (3x-1) = - 3x + 1
3x-2x=-3+1 2x+3x=1+3
x=-2 5x=4
x=4/5
|2x-3|=3x-1
2x-3 = 3x-1 or 2x-3 = - (3x-1) = - 3x + 1
3x-2x=-3+1 2x+3x=1+3
x=-2 5x=4
x=4/5
When the substitution method is used to solve the equations 5x-2 = y, 2x-3y = 1, the method is correct? A.2x-3x = 1 b.2x-15x + 3 = 1 c.2x-3 (5x-2) = 1 d.2x-15x-6 = 1
y=5x-2
So 2x-3y is 2x-3 (5x-2) = 1
Choose C
Solving equation (2x + 4) / 5 - (x-1) = (2x + 3) / 3 - (3x-2) / 2
(2x+4)/5-(x-1)=(2x+3)/3-(3x-2)/2 → 6(2X+4)-30(X-1)=10(2X+3)-15(3x-2) → 12X+24-30X+30=20X+30-45X+30 → -18X+54=-15X+60 → -3X=6 → X=-2