Contact us
Choose a category below so we can get back to you as quickly as possible.
設這兩個自然數為a,b,則可得運算式(1/a-1/b)*(19/28)=19/93 兩邊同時乘以28/19,得1/a-1/b=28/93,又1/a-1/b=(b-a)/ab 即(b-a)/ab=28/93,且a,b為自然數,故 b-a=28,ab=93,解該2元一次方程得a=3或-31(舍去),b=31 答:這兩個自然數分別為3,31
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.