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∵0≤x≤π2,∴π6≤x+π6≤2π3;∴當x+π6=π2時,函數取得最大值是y=sin(x+π6)=1;當x+π6=π6時,函數取得最小值是y=sin(x+π6)=12;∴函數y=sin(x+π6)的值域是[12,1].故答案為:[12,1].
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