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|Xn-0|=[1+(-1)^n]/n≤2/n 對於任意給定的正數ε,要使得|Xn-0|<ε,只要2/n<ε,即n>2/ε.取正整數N=[2/ε],當n>N時,|Xn-0|<ε. 所以,lim(n→∞)Xn=0 ----- [x]是取整函數
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