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直線2x-y-4=0即y=2x-4,斜率為k1=2,與x軸的交點為點(2,0) 逆時針方向旋轉π/4所得直線斜率為 k=(k1+tan(π/4))/(1+k1*tan(π/4))=(2+1)/(1-2*1)=-3 又因為直線過(2,0) 囙此所得直線方程為y=-3(x-2)即3x+y-6=0
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