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設C的X座標為x,則C點為C(x,0),我們知道三角形面積為底邊乘高除2,則有|ac|*5/2=6, 即|x-(-2)|=12/5,解得(x+2)=12/5或-(x+2)=12/5. 解得x=2/5或者x=-22/5,即滿足條件的C有兩點, C(2/5,0)或C(-22/5,0).
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