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∫(tanx/x³;)dx=(-1/2)∫tanx d(1/x²;)=-(1/2)tanx*(1/x²;)+(1/2)∫(1/x²;)[1/(1+x²;)]dx=-[(tanx)/(2x²;)]+(1/2)∫dx/x²;-(1/2)∫[1/(1+x²;)]dx=-[(tanx)/(2x²;)] -[1/(2x)]…
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