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假設1/a+1/b=1(a≠b),那麼(a+b)/(ab)=1(a≠b),a+b=ab(a≠b),因此滿足述條件的所有數都可以.如果a為3,那麼3+b=3b,求出b=3/2,我們來算一下,1/a+1/b=1/3+1/(3/2)=1/3+2/3=1,成立吧.所以滿足a+b=ab(a≠b)條件的所有數都...
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