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設X/(A-B)=Y/(B-C)=Z/(C-A)=k 所以X=(A-B)k,Y=(B-C)k,Z=(C-A)k 所以X+Y+Z=(A-B)k+(B-C)k+(C-A)k =(A-B+B-C+C-A)k =0×k =0
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