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由題設可知,直線L2上的任意一點P(x,y)關於直線L:3x-y-1=0的對稱點Q((-4x+3y+3)/5,(3x+4y-1)/5)必在直線L1:x+2y+1=0上,∴[(-4x+3y+3)/5]+[2(3x+4y-1)/5]+1=0.整理即得直線L1的方程:2x+11y+6=0.
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