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2x/(x+1)=a/(x+2)+1/[(x+2)(x+1)] 方程兩邊同時乘以(x+2)(x+1)得:2x(x+2)=a(x+1)+1 增根只可能為-1或-2 x=-1代入上式得:-2(-1+2)=1,不符 x=-2代入上式得:0=-a+1,得:a=1 囙此只能為a=1
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