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設z=x+yi(x,y∈R),得:x+yi-2√(x^2+y^2)=-7+4i ∴x-2√(x^2+y^2)=-7和y=4 ∴x^2+14x+49=4x^2+64 3x^2-14x+15=0 解得x1=3,x2=5/3 ∴z=3+4i或z=5/3+4i
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