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畢氏定理的所有整數解可以表示為:a=m²;-n²;,b=2mn,c=m²;+n²;(這個事可以證明的,其中m、n為正整數且不相等,a、b為直角邊,c為斜邊.)如果是連續數位,那麼一定有c是最大的,c-a=2n²;≥2,所以只能…
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