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x²;-2=0(x-1)²;/(x²;-1)+x²;/(x+1)=(x-1)²;/[(x-1)(x+1)]+x²;/(x+1)=(x-1)/(x+1)+x²;/(x+1)=(x²;+x-1)/(x+1)=(x+1)/(x+1)=1此題如仍有疑問,歡迎追問!
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