,f(x)=a-2/(2的x次方+1)(x)∈R為奇函數,球a 化簡消不了= =

,f(x)=a-2/(2的x次方+1)(x)∈R為奇函數,球a 化簡消不了= =

f(x)=a-2/(2^x+1)
x∈R
f(x)是奇函數
∴f(0)=0
a-2/2=0
a=1