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x−y−z=0 ; ;①x+y−3z=4 ; ;②2x+3y−5z=14 ; ;③,①+②得:2x-4z=4④,①×3+③得:5x-8z=14⑤,④×2-⑤得:-x=-6解得:x=6,把x=6代入④得:z=2,把x=6,z=2代入①得:y=4,則原方程組的解為:x=6y=4z=2.
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