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自然數平方和公式為n(n+1)(2n+1)/6,其中n為最後一比特自然數.由(5)代入(2)得自然數偶數平方和公式為2n(n+1)(2n+1)/3,其中2n為最後一比特自然數. 由(5)代入(3)得自然數奇數平方和公式為n(2n-1)(2n+1)/3,其中2n-1為最後一比特自然數.
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